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Unable to include chr(0) in string necessary to build an empty ZIP file.


NDTC
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Hi,

I found on this forum a topic who can create an Easy Zip Compression using Windows XP buid by Mozart90.

Her the code:

$ZipArchive = "c:\temp\tmp.zip"; Put here the full path and name ame of archive you would like to create
$AddFile = "c:\autoexec.bat"; Put here the the File you would like to compress in the zip   
$AddFile2 = "c:\config.sys"; Take another File ...

$oShell = ObjCreate("Shell.Application"); Create s shell Object

if IsObj($oShell) then              
    InitZip($ZipArchive); Create an emtpy zip file with header    
    $oDir = $oShell.NameSpace($ZipArchive); Use the zip file as an "Folder"
    $oDir.CopyHere ($AddFile); Copy a file in the "Zip Folder" 
    $oDir.CopyHere ($AddFile2); Copy a second file
    sleep (500); Give the Objekt a litte bit time to work 
else 
    Msgbox (0,"Error","Error creating Object.")
endif 

Func InitZip ($zip_path_name)
    $init_zipString= Chr(80) & Chr(75) & Chr(5) & Chr(6);Create the Header String 
        for $n =1 to 18;the     
            $init_zipString= $init_zipString & Chr(0);Header    
        next 
    $file =FileOpen($zip_path_name,2)                  
    FileWrite($file,$init_zipString);Write the string in a file 
    FileClose($file)
EndFunc

I use the last version of AutoIT (v3.2.10.0).

but the $init_zipString= $init_zipString & Chr(0) not work.

See this Hexa editor screenshot attached to view this the file: post-35156-1209571292_thumb.jpg

The second file is an empty ZIP file created by WinXP.

Can you help me please?

If anyone have a solution, or another methode to simply build an Empty ZIP file!!!

Thank's by advance,

Regards.

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Chr(0) is EOF to AutoIt in a string. You might want to assemble that header in a Binary(), and use binary mode for the FileOpen() before writing it.

:)

P.S. Demo (untested, please try it and check with your disk editor):

Func InitZip ($zip_path_name)
    $bin_zipString = Binary("0x504B0506000000000000000000000000000000000000")
    $file = FileOpen($zip_path_name,2 + 16) ; binary mode                 
    FileWrite($file,$bin_zipString);Write the binary in a file
    FileClose($file)
EndFunc

P.P.S. Tweaked second instance of variable name $bin_zipString.

Edited by PsaltyDS
Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law
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Great!!!!

It's ok... I search since 2 hours, and you found this in 4 minutes...

I searching an another function, but I am sure that others have already created several time: find the parent directory that a folder:

"c:\drivers\test" -> "C:\Drivers" is the parent directory of "Test"

Have you an idea?

Thank you very much...

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Great!!!!

It's ok... I search since 2 hours, and you found this in 4 minutes...

I searching an another function, but I am sure that others have already created several time: find the parent directory that a folder:

"c:\drivers\test" -> "C:\Drivers" is the parent directory of "Test"

Have you an idea?

Thank you very much...

I made this myself because i don't like _Path* functions:

Func _PathDir(Const $Path)
    Local $Pos = StringInStr($Path,"\",0,-1)
    IF Not $Pos Then
        $Pos = StringInStr($Path,"/",0,-1)
        IF NOT $Pos Then
            Return ""
        EndIf
    EndIF
        
    Return StringLeft($Path,$Pos - 1)
EndFunc

By the way,i'm having problems with binary strings to.

I need to format a string like this: "C:\test1\whatever.txt\0\0whatsoever.txt\0\0somemore.txt\0" where \0 are Chr(0) (NULL if you prefer)

How can i do this? (Forgot:the files are in an array,so stringformat won't work)

Edited by danielkza
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By the way,i'm having problems with binary strings to.

I need to format a string like this: "C:\test1\whatever.txt\0\0whatsoever.txt\0\0somemore.txt\0" where \0 are Chr(0) (NULL if you prefer)

How can i do this? (Forgot:the files are in an array,so stringformat won't work)

Why would you want to do that in a string (vice a binary)? Where is that a valid format?

It's not hard to generate as a binary:

Global $avString[3] = ["C:\test1\whatever.txt", "\0whatsoever.txt", "\0somemore.txt"]
Global $binData = ""

For $n = 0 To UBound($avString) - 1
    $binData &= Binary($avString[$n]) & Binary("0x00")
Next

ConsoleWrite("$binData = " & $binData & @LF)

:)

Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law
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Why would you want to do that in a string (vice a binary)? Where is that a valid format?

It's not hard to generate as a binary:

Global $avString[3] = ["C:\test1\whatever.txt", "\0whatsoever.txt", "\0somemore.txt"]
Global $binData = ""

For $n = 0 To UBound($avString) - 1
    $binData &= Binary($avString[$n]) & Binary("0x00")
Next

ConsoleWrite("$binData = " & $binData & @LF)

:)

This format is used in windows SHFileOperation function,it's really weird and unusual,but so is all the Windows API.And the problem is that the function does not accept binary data,so i should just use BinaryToString()?

EDIT:Quote from MSDN:

Although this member is declared as a single null-terminated string, it is actually a buffer that can hold multiple null-delimited file names. Each file name is terminated by a single NULL character. The last file name is terminated with a double NULL character ("\0\0") to indicate the end of the buffer.

Edited by danielkza
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