RAMzor Posted June 19, 2008 Share Posted June 19, 2008 (edited) I have a string like this: "VERSION3.9.312ASSY1A4E13F0B" or "Major.MinorSystemVersion21.0Test123" How can I strip special char () and extract DIGIT and dots (3.9.312 or 21.0) only between two word's ? This not work as required : $array = StringRegExp($str, "VERSION(.*)ASSY", 1) MsgBox(0, "***", $array[0]) Edited June 19, 2008 by RAMzor Link to comment Share on other sites More sharing options...
Monamo Posted June 19, 2008 Share Posted June 19, 2008 I have a string like this: "VERSION3.9.312ASSY1A4E13F0B" or "Major.MinorSystemVersion21.0Test123" How can I strip special char () and extract DIGIT and dots (3.9.312 or 21.0) only between two word's ? This not work as required : $array = StringRegExp($str, "VERSION(.*)ASSY", 1) MsgBox(0, "***", $array[0]) Slight modification of your code, with updated entry for the special character (Chr(7)): $sSource = "VERSION3.9.312ASSY1A4E13F0B" $sPattern = "VERSION(.*)ASSY" $array = StringRegExp(StringReplace($sSource,Chr(7)," "), $sPattern , 1) MsgBox(0, "***", $array[0]) - MoChr(77)& Chr(97)& Chr(100)& Chr(101)& Chr(32)& Chr(121)& Chr(97)& Chr(32)& Chr(108)& Chr(111)& Chr(111)& Chr(107)-------I've told you 100,000 times not to exaggerate!-------Don't make me hit you with my cigarette hand...-------My scripts:Random Episode Selector, Keyboard MouseMover, CopyPath v2.1, SmartRename for XP,Window Tracer[sup]New![/sup] Link to comment Share on other sites More sharing options...
zorphnog Posted June 19, 2008 Share Posted June 19, 2008 Or: $array = StringRegExp($str, "VERSION\D*((?:\d|\.)+)\D*ASSY", 3) If @error = 0 Then MsgBox(0, "***", $array[0]) Link to comment Share on other sites More sharing options...
RAMzor Posted June 19, 2008 Author Share Posted June 19, 2008 Thank you very much, it works! It is very difficult to deal with this syntax. Link to comment Share on other sites More sharing options...
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