Burgs Posted June 23, 2008 Share Posted June 23, 2008 Hi, The following code is contained within a script. The error message is being triggered upon execution because the file cannot be opened/read. That should not be the case. Is there an obvious error with this? It should "Close" the file even after the error is thrown, correct? ;write to the "source" file (erase) $source = FileOpen("C:\Documents and Settings\My Documents\1517.txt", 10) ;Check if file opened for reading OK If $source = -1 Then MsgBox(0, "Error", "Unable to open 1517 file.") Exit EndIf FileWriteLine($source, $PASS & " " & $AsDIFF & " " & $AgDIFF & " ") FileClose($source) Link to comment Share on other sites More sharing options...
Valuater Posted June 23, 2008 Share Posted June 23, 2008 test ok... Autoit 3.2.12.0 Win Xp sp2 ;write to the "source" file (erase) $source = FileOpen("C:\15177.txt", 10) ;$source = FileOpen("C:\Documents and Settings\My Documents\1517.txt", 10) ;Check if file opened for reading OK If $source = -1 Then MsgBox(0, "Error", "Unable to open 1517 file.") Exit EndIf FileWriteLine($source, "test") ;$PASS & " " & $AsDIFF & " " & $AgDIFF & " ") FileClose($source) ShellExecute("C:\15177.txt") 8) Link to comment Share on other sites More sharing options...
PsaltyDS Posted June 23, 2008 Share Posted June 23, 2008 (edited) Hi, The following code is contained within a script. The error message is being triggered upon execution because the file cannot be opened/read. That should not be the case. Is there an obvious error with this? It should "Close" the file even after the error is thrown, correct? ;write to the "source" file (erase) $source = FileOpen("C:\Documents and Settings\My Documents\1517.txt", 10) ;Check if file opened for reading OK If $source = -1 Then MsgBox(0, "Error", "Unable to open 1517 file.") Exit EndIf FileWriteLine($source, $PASS & " " & $AsDIFF & " " & $AgDIFF & " ") FileClose($source) There is usually a @UserName within that path. "My Documents" would not be directly under "Documents and Settings". You might try forming a path like: $sFile = @MyDocumentsDir & "\1517.txt" $hFile = FileOpen($sFile, 10); Overwrite, create path If $source = -1 Then MsgBox(0, "Error", "Unable to open 1517 file.") Else FileWriteLine($source, $PASS & " " & $AsDIFF & " " & $AgDIFF & " ") EndIf FileClose($source) If that is not the problem, why do you say "That should not be the case"? Can you delete/create that file in that location from the command line? If the file is not opened, then there is nothing to close, but your script won't execute FileClose() after the error because of the "Exit" right after the MsgBox(). Upon Exit, AutoIt automatically closes all open files/handles. Edited June 23, 2008 by PsaltyDS Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law Link to comment Share on other sites More sharing options...
Burgs Posted June 24, 2008 Author Share Posted June 24, 2008 Thanks for the response. I say "that should not be the case" because the file exists. I can open/close/edit it manually without any issue. Is there a way to somehow determine why the error is occuring/why the file cannot be opened? Thanks for the info about the "Exit", I wasn't aware handles would be automatically manipulated like that. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now