Hex ^ Hex?

[alex OF DEATH]

Well, I'm trying to do some relatively simple math here.. but not with integers.

I have an array with a series of strings such as "FF" and "0C" .. which, as you probably know, are hex bytes.

Now, using each hex byte from the array, I want to take it to the power of 0x61. Technically, I'm doing this: 0x61 ^ "FF" ... But FF is a string, and not actual hex. Even if I add 0x.. it's still "0xFF" (which is still a string)

I tried making each byte a decimal with Dec(),, then doing 97 ^ Dec($arraywithhexinstringform) but.. it usually just returned "#INF" (?)

Anybody see a way to do this? here's what I have right now: Thanks in advance

#Include <String.au3>
#Include <WinAPI.au3>

global $pakbytes[13]
global $decryptedpak[13]


$recv = "0x0B00C5661A0F6160610000" ; the hex

$recvpak = StringTrimLeft ( $recv, 0 ) ;nevermind this
$size = StringLen ($recvpak) / 2 ;how many bytes (2 chars per byte)

for $i = 0 to $size
    $pakbytes[$i] = StringLeft ( $recvpak, 2 ) ;for each byte (two characters), add into $pakbytes[]
    $recvpak = StringTrimLeft( $recvpak, 2 ) 
next


for $i = 1 to ubound($pakbytes) - 1
;   consolewrite($pakbytes[$i] & @CR)
next

;consoleWrite("DECRYPTED::" & @CR)
    
for $i = 2 to ubound($pakbytes) - 2 ;for i to how many bytes (except first two and last two)
    $decryptedpak[$i] = 0x61 ^ $pakbytes[$i]
    consoleWrite($decryptedpak[$i] & @CR)
next

[UPSman2]

MsgBox(0,"",97^255)

returns infinity too, only because its a huge number (its equalivanlt to "0x61"^"0xFF")

so its probably not your math or way of conversion that is messing up it's just that autoit doesn't support such large numbers

Edited July 7, 2008 by UPSman2

[alex OF DEATH]

MsgBox(0,"",97^255)

returns infinity too, only because its a huge number (its equalivanlt to "0x61"^"0xFF")

So.. is there anything I can do?

[UPSman2]

So.. is there anything I can do?

i don't know any solution but i'm not that great at math nor autoit... so there might be an answer but i don't know it

[alex OF DEATH]

You tell me- I'm trying to convert this:

unsigned short paksize=(*((unsigned short*)&packet[0])) - 2;
    for(int i=2; i<paksize; i++) 
    {
        packet[i] = 0x61 ^ packet[i];
    }

I have almost zero practical experience with any variant of C.

--??? Someone's post here vanished. Oh well.

Edited July 7, 2008 by alex OF DEATH

[SmOke_N]

You tell me- I'm trying to convert this:

unsigned short paksize=(*((unsigned short*)&packet[0])) - 2;
    for(int i=2; i<paksize; i++) 
    {
        packet[i] = 0x61 ^ packet[i];
    }

I have almost zero practical experience with any variant of C.

--??? Someone's post here vanished. Oh well.

Ummm... in C ... ^ = XOr (Could have been found with google)

$packet[$i] = BitXOr(0x61, $packet[$i])

[Richard Robertson]

Ah. I had actually asked this but then deleted my post. Maybe I should have kept it...

Yes, the ^ symbol in C++ is not to-the-power-of. It is XOR.