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Noob. Sorry. help?


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As the title says, I JUST started toying with autoit (or anything else for that matter) and am totally clueless.

The code will probably make it clear what I am trying to do, but essentially I just want a message box to appear if a password entered is correct, and a different one if it isn't. With the current code, I get the error message:

Error: Incorrect number of parameters in function call.

What am I doing wrong?

CODE
$pw = InputBox ("Security Check, Please enter your password, "", "*"")

If ("$pw=password") Then

MsgBox ("Security Check, Password Accepted!")

Else

MsgBox ("Security Check, Sorry, try again.")

EndIf

I know there is a better way of doing it, again I am just doing it for the sake of knowing how. Thanks

Christianity: In the beginning, there was God, who always was there and created everything.Atheism: In the beginning, there was nothing, which exploded. Both sides look bad...

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alot of syntax errors dude....

$pw = InputBox("Security Check", "Enter your password.", "", "*")
If $pw = "password" Then
    MsgBox(0, "Security Check", "Password Accepted!")
Else
    MsgBox(0, "Security Check", "Sorry, try again.")
EndIf

mouse not found....scroll any mouse to continue.

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