SRandom() and it uses

[nitekram]

Well I read the help file and still am not sure - is it so that you can predict your random number?

[Marlo]

That is indeed odd

Ran this script:

Local $Rand
For $I = 1 To 50
SRandom(12)
$rand &= Random(64, 800) & @CRLF
Next
MSgBox(0, "", $Rand)

And i just got the same number 50 times. : /

[Pain]

This function initializes the random number generator by setting the state table values based on seed. Then it cycles the state information for a fixed number of times to get rid of any initial dependencies. The state table information affects the returned random numbers of the subsequent random() calls.

[Mobius]

That is indeed odd

Ran this script:

Local $Rand
For $I = 1 To 50
SRandom(12)
$rand &= Random(64, 800) & @CRLF
Next
MSgBox(0, "", $Rand)

No wonder you were getting the same number

[Szhlopp]

SRandom is a SEEDED random number.

That seed will generate the same number everytime. Inlcuding on multiple computers.

As Mobius showed. It will generate the same series of numbers if it's not called everytime.

Make sense?

[nitekram]

SRandom is a SEEDED random number.

That seed will generate the same number everytime. Inlcuding on multiple computers.

As Mobius showed. It will generate the same series of numbers if it's not called everytime.

Make sense?

I wish - lol

So if you call it right before a Random() call it will generate the same number each time and if not like in Mobius example it will be a unique number?

[ProgAndy]

You could do something like this to initialise it new each zime:

Func _MakeRandomSRand()
    SRandom(Round((TimerInit()*Random(1234,3335789,1)+TimerInit())/TimerInit()))
EndFunc