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hi, how can i get only the file name from a path?

for example how can i get only the file names without fullpath from the following variables?

$CmdLine[0]

$CmdLine[1]

$CmdLine[2]

; and so on...

or

$A1 = "C:\New Folder\Images\Old\1.bmp"
$B2 = "D:\Songs\Audio\PoP\Loveme.Mp3"
$C3 = "E:\Video\Songs\YouTube\SimSim.Flv"
$D4 = "F:\Softwares\AutoItScripts\Compiled\MyProgram.exe"
; And so on...
MsgBox(64, "File Names", $A1 & @CRLF & $B2 & @CRLF & $C3 & @CRLF & $D4)

the above code will show a message box with the paths and there names like

F:\Softwares\AutoItScripts\Compiled\MyProgram.exe

but i want to show only the file name in message box like

MyProgram.exe

how can i extract the only name from path? i have many other paths to add so any easy, fast and good example?

thankss.

Edited by Cdma1X
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Hi Cdma1X,

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Help File + _PathSplit()

thanks for the quick answer. any example in showing it in messagebox? i could not understand ArrayDisplay().

#include <file.au3>
#include <array.au3>
Dim $szDrive, $szDir, $szFName, $szExt
$TestPath = _PathSplit(@ScriptFullPath, $szDrive, $szDir, $szFName, $szExt)
_ArrayDisplay($TestPath,"Demo _PathSplit()")oÝ÷ Ú+kçZºÚ"µÍÙÐÞ
    ][ÝÑ[H[YÉ][ÝË  ÌÍÕÝ]   [ÈÔ   [È ÌÍÑ[[ÈÔ]Ü]

J

thankss.

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$A1 = "C:\New Folder\Images\Old\1.bmp"
$B2 = "D:\Songs\Audio\PoP\Loveme.Mp3"
$C3 = "E:\Video\Songs\YouTube\SimSim.Flv"
$D4 = "F:\Softwares\AutoItScripts\Compiled\MyProgram.exe"
; And so on...

$A1 = StringRegExpReplace($A1, "^.*\\", "")
$B2 = StringRegExpReplace($B2, "^.*\\", "")
$C3 = StringRegExpReplace($C3, "^.*\\", "")
$D4 = StringRegExpReplace($D4, "^.*\\", "")

MsgBox(64, "File Names", $A1 & @CRLF & $B2 & @CRLF & $C3 & @CRLF & $D4)

 

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thanks MrCreatoR it is good. but i want to know/learn if there are any other ways to do it in future.

thanks once again.

#Include <File.au3>

Dim $szDrive, $szDir, $szFName, $szExt
$string = ""

$array = _FileListToArray(@ScriptDir, "*", 1)

For $i = 1 to $array[0]
    $TestPath = _PathSplit($array[$i], $szDrive, $szDir, $szFName, $szExt)
    $string &= $TestPath[3] & $TestPath[4] & @CRLF
Next

MsgBox(0,"test",$string)
Edited by SoulA
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thankss SoulA is it the last way or there are any more funcs/commands available?

my problem is solved by the script of MrCreatoR but i want to know more just for learning purposes.

thankss once again for the information.

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The code I wrote as the quickest and easiest way I can think of to get the just the file names of all the files in a given directory.

However, like everything there is always many ways to do something.

It is likely that the UDF you speak of if it exists uses one of the already mentioned options in this thread just in a UDF format.

Edited by SoulA
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  • Moderators

thankss SoulA if this UDF is available then can i have it's link?

as i told before i searched for the UDF but no results found/match the same.

MrCreator presented the fastest way. I merely suggested the help file way.

MrCreator is using Regular Expressions to move through the string of the file name.

StringRegExpReplace($D4, "^.*\\", "")

^ lets the regular expression engine know to start at the beginning of the string.

.* tells the engine to go through every possible character until it reaches it's stopping point which is back slash

\\ Is an escaped character, there is only one back slash but because a backslash has more than 1 meaning in Regular expression you have to escape it, just so happens, the escape character is also a backslash.

So what the ^.*\\ is doing in StringRegExpReplace is replacing every character between the start of the string, and the last backslash... thus leaving the file name + extension.

Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.

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Thanks for the detailed information which i could not get in help file and could not understand.

i have many variables to get path. any way to handle all of them with some short lines?

or any UDF which can get the file path without always writing the all lines?

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Thanks for the detailed information which i could not get in help file and could not understand.

i have many variables to get path. any way to handle all of them with some short lines?

or any UDF which can get the file path without always writing the all lines?

Depends on your naming conventions.

I prefer to use arrays... And MrCreators suggested method. This would only require 3 or 4 lines of code total.

You could look at Assign and Eval to do a For/Next loop to accomplish something similar with the same method as an array.

Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.

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Thanks Smoke_N

i have just accomplished what i want but only i have a last problem.

on running this

StringRegExpReplace($File_Group_A6, "^.*\\", "")

As you can see here, it works fine.

Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.

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Thanks Smoke_N

please check this:

; $CmdLineRaw = Default
MsgBox(0, 0, StringRegExpReplace($CmdLineRaw, "^.*\\", ""))oÝ÷ Ú+pYl*ºZ¶Ø^zwh}ø¥zv¦zX¤z'æÉø¥zv¦z+ºtÞ²Ö®ÞØ^,"Xµ§Më-jíêºb²+Z¦,¹^jëhÖîú®¢×êÞßÛ'¡ê뢸­ßÛ,jeÉÚ"!jØ­ßÛ-¢Wm¡ÚÆÚÚrׯz¼­)à~º&çí¡ûazV¬µ¶ÉZ²®¶­sc²b33c´6ÖDÆæU&rÒFVfVÇ@¤×6t&÷Âb33c´6ÖDÆæU&rÂ7G&æu&VtW&WÆ6Rb33c´6ÖDÆæU&rÂgV÷Cµââ¢b3#²b3#²gV÷C²ÂgV÷C²gV÷C²oÝ÷ غ(«mëb¶W¢·¥ÈhÃ*.¶«z+ªê-zØ^­æ­¶Ú¶¬¶¸§*2¢èZ½ëh©iØî²ÙÛ¢¸­ZgËhºw^®ËZܨ»e¯zÚ,¶çrEè.ªÄÆ޲ȨƬ¶¢»¦Â)eº0¶*ÞvÚÌ®)àªç¬¶*'²X¤zØb±«­¢+ØìÀÌØí
µ1¥¹IÜôÕ±Ð)5Í  ½à À°ÀÌØí
µ1¥¹IÜ°MÑÉ¥¹IáÁIÁ± ÀÌØí
µ1¥¹IÜ°ÅÕ½Ð츨üÀäÈìÀäÈíðÅÕ½ÐìÅÕ½ÐìÅÕ½Ðì°ÅÕ½ÐìÅÕ½Ð줤
Would be a revision you could make to suit your needs.

Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.

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$explorer = "C:\WINDOWS\explorer.exe"
ConsoleWrite($explorer&@CRLF&"FileName:  "&getFileName($explorer)&@CRLF&"ParentDir: "&getParentDir($explorer)&@CRLF&"Extension: "&getExtension($explorer)&@CRLF)

Func getFileName($fpath)
    Return StringMid($fpath,StringInStr($fpath,"\",0,-1)+1)
EndFunc

Func getParentDir($fpath)
    Return StringMid($fpath,1,StringInStr($fpath,"\",0,-1))
EndFunc

Func getExtension($fpath)
    Return StringMid($fpath,StringInStr($fpath,".",0,-1)+1)
EndFunc

another way :P

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