StringInStr

[jezzzzy]

Trying to do a simple string search with this:

StringInStr($string,'%;')

However this returns 0. If I remove the semicolon it returns a value (just the wrong one). I also tried escaping the semicolon like this:

StringInStr($string,'%\;')

Still no deal. Can't seem to find out how to search for '%;'.

[exodius]

Trying to do a simple string search with this:

StringInStr($string,'%;')

However this returns 0. If I remove the semicolon it returns a value (just the wrong one). I also tried escaping the semicolon like this:

StringInStr($string,'%\;')

Still no deal. Can't seem to find out how to search for '%;'.

Using the following returns 11 (where it's located in the string) for me, does it not for you?

$string = "this is a %; string"

MsgBox (0, "", StringInStr($string, "%;"))

[jezzzzy]

Sure does. Looks like a misdiagnosis on my part. I will post a new topic with the actual problem. Turns out '%;' just wasn't in my string. But it should have been. Sorry for the bad post.

[exodius]

Sure does. Looks like a misdiagnosis on my part. I will post a new topic with the actual problem. Turns out '%;' just wasn't in my string. But it should have been. Sorry for the bad post.

LOL, it's all good.