_DateAdd function

[judgedk]

I tried severel things but cant get it to work.

$d1 = _NowCalcDate()
$M1 = _DateAdd("y" & "d", -1, $d1)

I know this dosent work, but i guess it says what i want to do.

Thanks

[Andreik]

I tried severel things but cant get it to work.

$d1 = _NowCalcDate()
$M1 = _DateAdd("y" & "d", -1, $d1)

I know this dosent work, but i guess it says what i want to do.

Thanks

#include <Date.au3>
$now = _NowCalcDate()
$add = _DateAdd("Y",-1,$now)
MsgBox(0,"DATE",$add)

[judgedk]

#include <Date.au3>
$now = _NowCalcDate()
$add = _DateAdd("Y",-1,$now)
MsgBox(0,"DATE",$add)

Thanks for the reply.

But your examble gives today's date -1 on the year.

I need to -1 on the date and -1 on the year.

Thanks.

[martin]

Thanks for the reply.

But your examble gives today's date -1 on the year.

I need to -1 on the date and -1 on the year.

Thanks.

I think you have enough information now to work out what to do!

Your example didn't work, Adreik's example did what you describe, the help tells you to use one letter and you used 2.

So just do it in 2 steps. Reduce by one year then by one day.

[PsaltyDS]

I think you have enough information now to work out what to do!

Your example didn't work, Adreik's example did what you describe, the help tells you to use one letter and you used 2.

So just do it in 2 steps. Reduce by one year then by one day.

As martin told you, you'll have to use two steps. Since AutoIt accepts nested function calls you could do:

$YearAndDayAgo = _DateAdd("D", -1, _DateAdd("Y", -1, _NowCalcDate()))

You might expect to be able to just do -366 days, but that will come out wrong for leap years.

[judgedk]

As martin told you, you'll have to use two steps. Since AutoIt accepts nested function calls you could do:

$YearAndDayAgo = _DateAdd("D", -1, _DateAdd("Y", -1, _NowCalcDate()))

You might expect to be able to just do -366 days, but that will come out wrong for leap years.

Thank you very much, been trying a lot of different things to get this working.. but not this