huskies Posted March 17, 2009 Share Posted March 17, 2009 with _DateTimeSplit it can split 2005/01/01 14:30 into date and time is there one that can split the date? <It Shall Be Done> Link to comment Share on other sites More sharing options...
BugFix Posted March 17, 2009 Share Posted March 17, 2009 (edited) with _DateTimeSplit it can split 2005/01/01 14:30 into date and time is there one that can split the date? Use string functions: $date = '2005/01/01 14:30' $year = StringLeft($date, 4) $mon = StringMid($date, 6, 2) $day = StringMid($date, 9, 2) MsgBox(0, 'Date', 'Year: ' & $year & @LF & 'Month: ' & $mon & @LF & 'Day: ' & $day) ; or with split $aDate = StringSplit(StringTrimRight($date, 6), '/') MsgBox(0, 'Date with StringSplit', 'Year: ' & $aDate[1] & @LF & 'Month: ' & $aDate[2] & @LF & 'Day: ' & $aDate[3]) Edited March 17, 2009 by BugFix Best Regards BugFix Link to comment Share on other sites More sharing options...
erik7426 Posted March 17, 2009 Share Posted March 17, 2009 Why not use _DateTimeSplit and just ignore the time values #include <Date.au3> #include <Array.au3> Dim $MyDate Dim $MyTime _DateTimeSplit("2009/03/17", $MyDate, $MyTime) _ArrayDisplay($MyDate,"Date Info") Link to comment Share on other sites More sharing options...
huskies Posted March 17, 2009 Author Share Posted March 17, 2009 (edited) Why not use _DateTimeSplit and just ignore the time values #include <Date.au3> #include <Array.au3> Dim $MyDate Dim $MyTime _DateTimeSplit("2009/03/17", $MyDate, $MyTime) _ArrayDisplay($MyDate,"Date Info") I meant how to turn 2009/03/17 into 2009 ,March and 17. I don't have a time variable, that was just an example. @BugFix, thank you , it was a very good idea! Edited March 17, 2009 by huskies <It Shall Be Done> Link to comment Share on other sites More sharing options...
erik7426 Posted March 17, 2009 Share Posted March 17, 2009 I meant how to turn 2009/03/17 into 2009 ,March and 17. I don't have a time variable, that was just an example. @BugFix, thank you , it was a very good idea! This would give you the name of the month if that is what you are looking for... #include <Date.au3> Dim $MyDate Dim $MyTime _DateTimeSplit("2009/03/17", $MyDate, $MyTime) $Year = $MyDate[1] $Month = _DateToMonth($MyDate[2],0) $Day = $MyDate[3] MsgBox(0,"","Year: " & $Year & @CRLF & "Month: " & $Month & @CRLF & "Day: " & $Day) Link to comment Share on other sites More sharing options...
Szhlopp Posted March 17, 2009 Share Posted March 17, 2009 I meant how to turn 2009/03/17 into 2009 ,March and 17. I don't have a time variable, that was just an example. @BugFix, thank you , it was a very good idea! I had to create this for someone a few months back. Modify it to your hearts content. #Include <Date.au3> MsgBox(0, "", _DateSubtract(-1)) Func _DateSubtract($iSubtract) Local $Days[7] = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday" ] Local $Month[12] = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"] $Split = StringSplit(_DateAdd('d', $iSubtract, _NowCalcDate()), "/") $CurentDate = $Days[_DateToDayOfWeekISO($Split[1], $Split[2], $Split[3])] & ", " & $Month[$Split[2] - 1] & " " & $Split[3] & ", " & $Split[1] Return $CurentDate EndFunc RegEx/RegExRep Tester!Nerd Olympics - Community App!Login UDFMemory UDF - "Game.exe+753EC" - CE pointer to AU3Password Manager W/ SourceDataFiler - Include files in your au3!--- Was I helpful? Click the little green '+' Link to comment Share on other sites More sharing options...
huskies Posted March 17, 2009 Author Share Posted March 17, 2009 This would give you the name of the month if that is what you are looking for... #include <Date.au3> Dim $MyDate Dim $MyTime _DateTimeSplit("2009/03/17", $MyDate, $MyTime) $Year = $MyDate[1] $Month = _DateToMonth($MyDate[2],0) $Day = $MyDate[3] MsgBox(0,"","Year: " & $Year & @CRLF & "Month: " & $Month & @CRLF & "Day: " & $Day) thank you, so in here is $myDate separating the 2009/03/17 into 3 arrays based on the slash "/" or does this only work on dates? say if i had "random/whatever/don'tknow" would it work? $Year = $MyDate[1] $Month = $MyDate[2] $Day = $MyDate[3] <It Shall Be Done> Link to comment Share on other sites More sharing options...
erik7426 Posted March 17, 2009 Share Posted March 17, 2009 thank you, so in here is $myDate separating the 2009/03/17 into 3 arrays based on the slash "/" or does this only work on dates? say if i had "random/whatever/don'tknow" would it work? $Year = $MyDate[1] $Month = $MyDate[2] $Day = $MyDate[3] If you try "random/whatever/don'tknow" each of the elements in $MyDate contains -1. So, you must have something that resembles a date in the format of yyyy/mm/dd in order for the function to work. Link to comment Share on other sites More sharing options...
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