StringInStr ("testXa","x",0,-1) why = 5 not 1 ?

[JackDinn]

$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now (it is late, no excuse)

[JackDinn]

nm, $test=StringLen($html-$test) will do, just looked like it should count backward to me from the description.

[SmOke_N]

$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now (it is late, no excuse)

The returned character position is always left to right.

[UEZ]

$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now (it is late, no excuse)

I doesn't matter from which side you start to search a character - the result will always counted from the left side!

If you need it from right side just reverse the string:

#Include <string.au3>
$html="Mary had a little l/amb"
$test=StringInStr(_StringReverse($html),"/" ,0)
MsgBox(0,"test",$test)

UEZ

[Yashied]

I doesn't matter from which side you start to search a character - the result will always counted from the left side!

If you need it from right side just reverse the string:

#Include <string.au3>
$html="Mary had a little l/amb"
$test=StringInStr(_StringReverse($html),"/" ,0)
MsgBox(0,"test",$test)

UEZ

I think that _StringReverse() will be slower than StringLen().

[JackDinn]

aye me to but thx for the input anyhow .