Get Filename From FileOpenDialog

[FinalVersion]

Current Code:

$sB = FileOpenDialog("Select A File...", @DesktopDir, "All Files (*.*)", 1 + 2)

I need to get the filename of what the user selects thanks.

[Yashied]

Current Code:

$sB = FileOpenDialog("Select A File...", @DesktopDir, "All Files (*.*)", 1 + 2)

I need to get the filename of what the user selects thanks.

StringRegExpReplace($sB, "^.*\\", ""))

[toonboon]

the $sB returns the full path of the file that has been selected. Try looking at stringsplit to acomplish it.

[FinalVersion]

This will work. I use it in one of my scripts.

$file = FileOpenDialog("Select A File...", @DesktopDir, "All Files (*.*)", 1 + 2)
$split = StringSplit($file, "\")
$filename = $split[$split[0]]
MsgBox(0,"Test",$filename)

Already found a fix, but your way is interesting + easier then mine Thanks