how to choose a point that is closest?

[6105]

I have this theorem for selection and the nearest point, but I do not understand how to work with her who can give an example or explain?

Func Pixel_Distance($x1, $y1, $x2, $y2);Pythagoras theorem for 2D
    Local $a, $b, $c
    If $x2 = $x1 And $y2 = $y1 Then
        Return 0
    Else
        $a = $y2 - $y1
        $b = $x2 - $x1
        $c = Sqrt($a * $a + $b * $b)
        Return $c
    EndIf
EndFunc;==>Pixel_Distance

Thank you guys in advance

how to choose a red points that is closest to the black?

Edited June 6, 2009 by toader

[Skruge]

You pass the function two sets of X/Y coordinates, and it will return the distance between them.

Your topic title is: "how to choose a point that is closest?"

Closest to what?

[qsek]

This function returns the distance in pixels from one point ($x1,$y1) to another Point ($x2,$y2)

If the x coords and y coords are equal Then
        Return 0 ; Point1 and Point2 have the same coords, distance 0
    Else
        $a = $y2 - $y1 ; get x distance between Points
        $b = $x2 - $x1 ; get y distance between Points
        $c = Sqrt($a * $a + $b * $ B) ; do pythagoras to get length
        Return $c ; return length
    EndIf

[6105]

You pass the function two sets of X/Y coordinates, and it will return the distance between them.

Your topic title is: "how to choose a point that is closest?"

Closest to what?

"how to choose a red points that is closest to the black? "

Updated post updated

[6105]

This function returns the distance in pixels from one point ($x1,$y1) to another Point ($x2,$y2)

If the x coords and y coords are equal Then
        Return 0 ; Point1 and Point2 have the same coords, distance 0
    Else
        $a = $y2 - $y1 ; get x distance between Points
        $b = $x2 - $x1 ; get y distance between Points
        $c = Sqrt($a * $a + $b * $ B) ; do pythagoras to get length
        Return $c ; return length
    EndIf

yes i know what is do but i dont understand how to use it

[qsek]

well you have problem with your approach to the whole task.

You have an image with an black dot and some random red dots.

You want to get the coordiantes of that red dot that is closest to the black dot.

So using a function which gets you the distance from two coords requires that you already know the coords of the points.

To make it complicated you would have to store every points coords in an array and make a loop where you get the distance to every point, store the distance with the coords, and in the end compare all distances to get the closest coords.

A bit complicated

I suggest you do a more "radar" style approach.

Use PixelGetColor to find the black dot.

Then run PixelGetColor in circles around the black with increasing the radius of the "scan" every turn.

If you find your first red pixel, thats the closest one

By the way: What game is that again? I remember that i've played it once ^^

Edited June 6, 2009 by qsek

[6105]

well you have problem with your approach to the whole task.

You have an image with an black dot and some random red dots.

You want to get the coordiantes of that red dot that is closest to the black dot.

So using a function which gets you the distance from two coords requires that you already know the coords of the points.

To make it complicated you would have to store every points coords in an array and make a loop where you get the distance to every point, store the distance with the coords, and in the end compare all distances to get the closest coords.

A bit complicated

I suggest you do a more "radar" style approach.

Use PixelGetColor to find the black dot.

Then run PixelGetColor in circles around the black with increasing the radius of the "scan" every turn.

If you find your first red pixel, thats the closest one

By the way: What game is that again? I remember that i've played it once ^^

$coord = PixelSearch( 170, 126, 960, 390, 0xFFFFFF );hero
$left = $coord[0]-100
$top = $coord[1]-100
$right = $coord[0]+100
$buttom = $coord[1]+100
$coord1 = PixelSearch( $left, $top, $right, $buttom, 0xFEAE2C );monster
If Not @error Then
     Send("{SHIFTDOWN}")
     MouseClick("primary", $coord1[0]+30, $coord1[1]+15, 1)
     Send("{SHIFTUP}")
     Send("d")
     Send("{SHIFTDOWN}")
     MouseClick("primary", $coord1[0]+30, $coord1[1]+15, 1)
     Send("{SHIFTUP}")
     Send("d")
EndIf

and I also use Square bc cant do circle in order to atack if monstar within a radius of 100 pixels to click on it 10 races

but how to make the radar does not come to mind: (

more Square? checkpixel in 1Square if in Square1 no redpixel checkpixel in 2Square if in Square2 no redpixel check..... y?

Edited June 6, 2009 by toader

[qsek]

and I also use Square bc cant do circle in order to atack if monstar within a radius of 100 pixels to click on it 10 races

but how to make the radar does not come to mind: (

more Square? checkpixel in 1Square if in Square1 no redpixel checkpixel in 2Square if in Square2 no redpixel check..... y?

lol do you use google translator? i can not really read what you say

Anyway i think this one will be used for making a bot, so good luck

[6105]

lol do you use google translator? i can not really read what you say

Anyway i think this one will be used for making a bot, so good luck

sry(( y i use google)) and y i wanna do bot but im in AutoIt 4 days and dont have big experience in this((

[6105]

well you have problem with your approach to the whole task.

You have an image with an black dot and some random red dots.

You want to get the coordiantes of that red dot that is closest to the black dot.

So using a function which gets you the distance from two coords requires that you already know the coords of the points.

To make it complicated you would have to store every points coords in an array and make a loop where you get the distance to every point, store the distance with the coords, and in the end compare all distances to get the closest coords.

A bit complicated

I suggest you do a more "radar" style approach.

Use PixelGetColor to find the black dot.

Then run PixelGetColor in circles around the black with increasing the radius of the "scan" every turn.

If you find your first red pixel, thats the closest one

By the way: What game is that again? I remember that i've played it once ^^

How to find all red points? if i searchpixel it find 1 point but how to find all?