Custom Query (3922 matches)
Results (313 - 315 of 3922)
| Ticket | Resolution | Summary | Owner | Reporter |
|---|---|---|---|---|
| #2548 | Rejected | Array Literal Notation | ||
| Description |
Please allow the use of the array literal notation as an expression and not only as an array initializer. Example: Local $data [2] = ["a", "b"] ; ... _ArrayConcatenate ($data, ["c", "d"]) |
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| #2604 | Rejected | Array access on expression & first element | ||
| Description |
Sorry for my English can be enabled (in Array access on expression) to read\access the first item\element directly (without specify it), example Local $aTest1[4] = [1,2,3,4], $aTest1[4] = ["One","Two","Three","Four"], $aTest3[4][4] = [[0,1,2,3],[4,5,6,7]] If ($aTest1) = 1 Then ;ect ect ect EndIf If ($aTest2) = "One" Then ;ect ect ect EndIf If ($aTest3) = 0 Then ;ect ect ect EndIf Ciao. |
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| #2283 | No Bug | Array access when using nested arrays | ||
| Description |
If arrays are nested then it is not possible to access them using brackets directly. Local $a1[3] = [0, 0, 0] Local $a2[3] = [1, 2, 3] $a1[2] = $a2 ;MsgBox(0, "Test", ($a1[2])[1]) ; Works MsgBox(0, "Test", $a1[2][1]) ; Doesn't Furthermore, using parenthesis like above to try and assign to that does nothing at all (no error, no effect): #include<Array.au3> Local $a1[3] = [0, 0, 0] Local $a2[3] = [1, 2, 3] $a1[2] = $a2 ($a1[2])[1] = 42 _ArrayDisplay($a1[2]) |
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