quick regex question

[diveboy]

hi,

wanting to StringRegExp the following string "2 NOTE Digger - Death Index. Victoria 1921-1985" as an example.

Want to get an array back splitting the first two white spaces and the rest as a string, so

[0]='2'

[1]='NOTE'

[3]='Digger - Death Index. Victoria 1921-1985" as an example.'

I'm using StringRegExp('2 NOTE Digger - Death Index. Victoria 1921-1985','\S+', 3 ) which returns each word between white spaces, I only need the first two white spaces split

[0]|2

[1]|NOTE

[2]|Digger

[3]|-

[4]|Death

[5]|Index.

[6]|Victoria

[7]|1921-1985

can someone tell me how to get regexp to act on the first two white spaces ?

Thanks

Michael.

[zorphnog]

$sSomething = "2 NOTE Digger - Death Index. Victoria 1921-1985"
$aResult = StringRegExp($sSomething, "(?U)(.+)\s(.+)\s(.*)\Z", 3)

[diveboy]

$sSomething = "2 NOTE Digger - Death Index. Victoria 1921-1985"
$aResult = StringRegExp($sSomething, "(?U)(.+)\s(.+)\s(.*)\Z", 3)

Thanks zorphnog, works a treat.

if your ever in Melbourne, look me up, first beer is on me!

[Mison]

Without regex:

#include <array.au3> ; for _ArrayDisplay
$string = "2 NOTE Digger - Death Index. Victoria 1921-1985"
$array = StringSplit(StringReplace($string," ","++delim101++",2),"++delim101++",3)
_ArrayDisplay($array)