WinActivate: how to identify the right window when several windows have the same title?

[Akshay07]

Hello all,

I am facing a problem with the use of WinActivate/WinWaitActive.

Both functions use the title and/or text to identify the window that should be used.

My problem is that I could end up by having several existing windows with exactly the same title (text unknown). I am talking about a Command Prompt window. This is not due to the way the script is made (the script will use only one instance of Command Prompt), I am just trying to consider the use case in which the user would open "manually" another Command Prompt while the script is running.

The script can of course know which PID is associated to the Command Prompt it should use, but I couldn't figure out a way to use the PID to identify a specific window that can be used with WinActivate/WinActive function.

One solution I though of was to disable the possibility of starting the same program manually while the script is running but:

1/ I have no idea how to do that

2/ I would prefer to use a solution that does not give any limitation to the user

Any direction to where to look at would be very welcome!

Thanks.

[martin]

You can use the pid returned by Run to identify it and you can set the title to identify it.

Func m1()

    $pid = Run("cmd", @scriptDir, @SW_SHOWNORMAL, $STDIN_CHILD + $STDOUT_CHILD)
    StdinWrite($pid, "title somethingunique876" & @CRLF);set the title
    sleep(4000);time to let you see the title
    StdinWrite($pid, "dir" & @CRLF)

    StdinWrite($pid, "exit" & @CRLF)
    While 1
    $line = $line & StdoutRead($pid)
    If @error Then ExitLoop
    WEnd

    MsgBox(0, "Stdout", $line)
    ProcessClose($pid)

EndFunc ;==>m1

[Akshay07]

Martin, you are (as often) my savior

Your example works like a charm. I need to work on it to adapt it to my script, but this is perfect!

Thank you very much