MiserableLife Posted July 9, 2010 Posted July 9, 2010 How come a binary number with quotes and without quotes has different binary length? Is it because it is stored in different datatypes inside AutoIt ? Thanks $bin0 = 0xB800 Msgbox(0,'',BinaryLen($bin0));BinaryLen = 4 $bin1 = "0xB800" Msgbox(0,'',BinaryLen($bin1));BinaryLen = 2
trancexx Posted July 9, 2010 Posted July 9, 2010 How come a binary number with quotes and without quotes has different binary length?To be able to understand the answer you have to understand what's wrong with your question. ♡♡♡ . eMyvnE
MiserableLife Posted July 9, 2010 Author Posted July 9, 2010 I wanted to ask my question, but I don't know how to express it. So I just did it even if it has a problem. How about this: What is the difference between 0x8B00 and "0x8B00" if there's no difference, then why BinaryLen(0x8B00) will return 4 and BinaryLen("0x8B00") returns 2 ?
trancexx Posted July 9, 2010 Posted July 9, 2010 What is the difference between 0x8B00 and "0x8B00"Former is number, latter not (string). ♡♡♡ . eMyvnE
MiserableLife Posted July 9, 2010 Author Posted July 9, 2010 Got it. Thanks~ ConsoleWrite(0xB800 & @CRLF) ConsoleWrite('0xB800' & @CRLF) ConsoleWrite(Binary(0xB800) & @CRLF) ConsoleWrite(Binary('0xB800') & @CRLF) ConsoleWrite(BinaryLen(0xB800) & @CRLF) ConsoleWrite(BinaryLen('0xB800') & @CRLF)
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now