Program Open File

[Kaeft]

I haven't the fondest as to what I should search for so I'll post and see what I can get.

Is there a function that will take a program and open a file. Like if I wanted to open a document for microsoft office it would be something like ProgramOpenFile(title - "microsoft office", text "", File to open "stuffnjunk.doc"). Or is Controlsend an "alt f o" then ControlSetText "the filename/path" the only way to do that?

Thanks in advance.

[omikron48]

Usually, those programs accept commandline parameters which can also be used for opening files.

Have you tried:

$officepath = 'C:\Program Files\Microsoft Office\Office12\" ;whatever the path to MS word is
$docfile = "test.doc" ;file you want opened
Run($officepath & "winword.exe " & $docfile)

EDIT: If you are looking for UDFs for Word or Excel, check the _Word* or _Excel* functions in the help file. As for other programs, not everything has a UDF of function, most specially the ones you normally do via commandline arguments.

Edited August 6, 2010 by omikron48

[Kaeft]

Usually, those programs accept commandline parameters which can also be used for opening files.

Have you tried:

$officepath = 'C:\Program Files\Microsoft Office\Office12\" ;whatever the path to MS word is
$docfile = "test.doc" ;file you want opened
Run($officepath & "winword.exe " & $docfile)

Ok yeah that would be pretty simple. If all else fails I will definitely use that. Thanks!

Would that work if the program was already running?

[omikron48]

I think it opens a new instance every time.

[muhmuuh]

I use the ShellExecute function

[omikron48]

That's if the program you want is associated to that particular file type. I'm tackling the case where you want an arbitrary program opening a particular file.