How to use IsInt function?

[nekokk]

$quan = inputbox("test","I need an integer",""," M")

;and then I typed a word "5"

If IsInt($quan) then

  MsgBox(0,"test","It's a Integer","")

endif

;The MsgBox never come out......

Did I use it with wrong way?

I would like to know what type the data returned from MsgBox is.

Please help me.

Thank you in advance.

Edited June 30, 2005 by nekokk

[buzz44]

Wrong function...

InputBox:

Return Value Success: Returns the string that was entered.

Keyword is string.

Now we look at the StringIsInt() function.

StringIsInt:

Checks if a string is an integer

$quan = inputbox("test","I need a integer",""," M")
If StringIsInt($quan) then
  MsgBox(0,"test","It's a Integer","")
endif
;The MsgBox never come out......

[nekokk]

Oh! it's my bad

Thank you Burrup.

I also have another problem, that is how to check a string returned from inputbox for plus and minus?

I would like the users to input integer for a number of array, so if them input a string not integer , it will get an error.

$quan = InputBox("Example", "I need an integer", ""," M")
If StringIsInt($quan) then; The users can still input an integer like -100, but this will cause   global $array[$quan][2] ; an error  to declare array.
                          ;How to check minus and plus of an integer?
EndIf

thank you in advance.

I found the function out.

Abs function can solve my problem.

$quan = InputBox("Example", "I need an integer", ""," M")
If StringIsInt($quan) then
   $quan = Abs($quan)
   global $array[$quan][2] 
EndIf

Edited June 30, 2005 by nekokk