Acquiring a string from the right side of a symbol in a text file

[TheCrimsonCrusader]

Greetings,

The script below will read the testfile.txt, that has the following contents:

path=c:\windows

It will then proceed to strip any text to the left of the equal sign including the equal sign i.e. so it shows up as c:\windows, which is the expected behavior. Alternately, I would like to strip any text that is right of the equal sign including the equal sign instead. Whether I change the "StringTrimLeft" to "StringTrimRight" or change the "1"/"-1" entries on the "$LeftofEqual" variable or both, I don't get the hopeful results of it showing up as path

I can't do any specific trim numbers as that will vary, so that's why I am acquiring the number of characters leading up to the equal sign, but I can't seem to reverse it where it acquires the number of characters from the right side of it instead. The full code is below:

$readline = FileReadLine("testfile.txt",1)
$LeftofEqual=StringInStr($readline, "=", 1, -1)
$result = StringTrimLeft ($readline,$LeftofEqual)
MsgBox(0,"",$result

Thanks in advance for any assistance that can be provided.

Edited August 16, 2011 by TheCrimsonCrusader

[enaiman]

Here you go:

$readline = FileReadLine("testfile.txt",1)
$LeftofEqual=StringInStr($readline, "=", 1, -1)
$result = StringTrimLeft ($readline,$LeftofEqual)
MsgBox(0,"",$result)
$result = StringTrimRight($readline, StringLen($readline)-$LeftofEqual+1)
MsgBox(0,"",$result)

To strip the right part - you need to consider string length.

Edited August 17, 2011 by enaiman

[Melba23]

TheCrimsonCrusader,

Or you can use a SRE like this to split on the = sign directly:

$sText = "path=c:\windows"

$sLeft  = StringRegExpReplace($sText, "(.*)=(.*)", "$1")
$sRight = StringRegExpReplace($sText, "(.*)=(.*)", "$2")

MsgBox(0, "Result", $sLeft & @CRLF & $sRight)

SRE explanation:

(.*)    - Capture any number of characters
=       - Do not capture an = sign
(.*)    - Capture any number of characters

$1      - Replace with first captured group
$2      - Replace with second captured group

Please ask if anything is unclear.

M23