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Posted

J1,

This is the kicker...

Given that this is a good file...

123_456

How do you determine this programmatically?

kylomas

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Posted

The only exception to this rule, is the good file, it is the only file where

both ends have dupes.

That being true, then this is indeed solved, twice i believe.

,-. .--. ________ .-. .-. ,---. ,-. .-. .-. .-.
|(| / /\ \ |\ /| |__ __||| | | || .-' | |/ / \ \_/ )/
(_) / /__\ \ |(\ / | )| | | `-' | | `-. | | / __ \ (_)
| | | __ | (_)\/ | (_) | | .-. | | .-' | | \ |__| ) (
| | | | |)| | \ / | | | | | |)| | `--. | |) \ | |
`-' |_| (_) | |\/| | `-' /( (_)/( __.' |((_)-' /(_|
'-' '-' (__) (__) (_) (__)

Posted

boththose,

That's where I was going last night when I dumped coffee all over my keyboard...

1 - winnow out all "good" files (code posted)

2 - process array of possibly good files finding all names where both nodes have dups (coffee interruptus..)

@J1,

Got other junk happenning, please post your solution.

Good Luck!

kylomas

Forum Rules         Procedure for posting code

"I like pigs.  Dogs look up to us.  Cats look down on us.  Pigs treat us as equals."

- Sir Winston Churchill

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