newlines in regex

[Ontosy]

I have in $a:

<a href='aaaa.aspx?id=123456&bbbbb=1234'>
                                                    <span

and use:

StringRegExp($a, "<a href='(aaaa.aspx\?id.[^\s].*?)'>(?s).*?<span", 3)

why return @Error?

how to use newlines in regex?

[czardas]

What do you mean by .[^s].

[czardas]

Oh well. I don't know exactly what you want. Maybe this helps.

#include <Array.au3>
$a = "<a href='aaaa.aspx?id=123456&bbbbb=1234'>" & @LF & _
"                                                   <span"

$regexp = StringRegExp($a, "<a href='(aaaa.aspx?id[^('>)]*'>[s]*<span)", 3)

_ArrayDisplay($regexp)

[Ontosy]

ty, it works.

[Jury]

<a href='(aaaa.aspx?id.[^s].*?)'>(?s).*?<span

1) [^s] means match a single character that is a "non-whitespace character"

2) do you mean to use the the . in the four places this means match any single character perhaps you mean . ?

3) it is common to use r?n to cover any CRLF or LF or CR newline possiblities

4) if using .*? to have better control it would be best to start with (?-s) meaning match the remainder of the regex with the options: dot does not match newline - then you can replace all the .[^s].*?) with just .*?.> because an <a href will always end in a single chr (" or ') followed by >

but as you may know there are as many ways of doing regex as there are people, like me, making comments!

#include <Array.au3>
$a = "<a href='aaaa.aspx?id=123456&bbbbb=1234'>" & @CRLF & _
"                                                  <span"
$regexp = StringRegExp($a, "(?-s)<a href='(aaaa.aspx?id.*?.>r?n.*?n)", 3)
_ArrayDisplay($regexp)

[GEOSoft]

instead of r?n you can simply use v+

that will catch return and/or newline characters