Random Pixel Search

[Thatsgreat2345]

Ok i was wondering if there was a possibility of having it so my script would randomly search for a certain color but the thing is when i have it search it finds the same place each time i was wondering if there was any way to make it find the area then click randomly somewhere with in 1-5 on the x and y cuz when it checks the box it finds the pixel but clicks the same spot every time since it keeps searching for the same pixel and it doesnt matter if u put a shade variation or a step on it cuz it will always find the same pixel.

expandcollapse popup

Global $Paused
HotKeySet("{f2}", "TogglePause")
HotKeySet("{ESC}", "Terminate")
HotKeySet("{f1}", "ShowMessage") ;Shift-Alt-d

;;;; Body of program would go here;;;;
While 1
sleep(100)
WEnd
;;;;;;;;

Func TogglePause()
    $Paused = NOT $Paused
    While $Paused
        sleep(100)
        ToolTip('Script is "Paused"',0,0)
    WEnd
    ToolTip("")
EndFunc

Func Terminate()
    Exit 0
EndFunc

Func ShowMessage()
    While 1
$Coord = PixelSearch ( 371, 388, 533, 434, 0xFCB131, 0, 4)
sleep(500)
$Coord1 = PixelSearch ( 371, 388, 533, 434, 0x243302, 0, 4)
   If Not @error Then
      MouseClick ( "Left" , $Coord[0], $Coord[1] , 1 , 0 )
      sleep(3500)
      MouseClick ( "Left" , $Coord1[0], $Coord1[1] , 1 , 0 )
      sleep(3500)
  EndIf
WEnd
Endfunc

[layer]

Could you please remove that quote from your profile... I'm not stuck up, but I'm all about equality.

To try and answer your question:

Func ShowMessage()
    While 1
$Coord = PixelSearch ( 371, 388, 533, 434, 0xFCB131, 0, 4)
sleep(500)
$Coord1 = PixelSearch ( 371, 388, 533, 434, 0x243302, 0, 4)
   If Not @error Then
      MouseClick ( "Left" , $Coord[0] + Random(1, 5), $Coord[1] -  Random(1, 5), 1 , 0 )
      sleep(3500)
      MouseClick ( "Left" , $Coord1[0] + Random(1, 5), $Coord1[1] -  Random(1, 5), 1 , 0 )
      sleep(3500)
  EndIf
WEnd
Endfunc

I didn't test it, so let me know how it works.

[Thatsgreat2345]

removed sig and thanks for the help it works

[layer]

removed sig and thanks for the help it works

Thanks.