How to display line numbers of input file

[Ghost1982]

Hello

 

Is there any way how I can display line numbers of an input file.

Let's say i've got list of AD groups to create (i.e. 1000 of them) in some input file. What I would like to do is to display in the console screen current line that is being processed. Thanks to that I know how far the script is

For now, what I'm doing is that

$content = Get-Content input.txt
Foreach ($ADgrp in $content ) {
     Write-host Creating AD group: $ADgrp
     New-AdGroup -Name "$ADgrp" -SamAccountName $ADgrp etc.
     Start-Sleep 3
}

So in the console window I wil lreceive:

Creating AD group: <some group name>

But I would like to have something like this:

Processing 1 of 1000 lines
Creating AD group: <some group name>

Processing 2 of 1000 lines
Creating AD group: <some group name>

etc.

 

How can I add the "counter" within Foreach loop?

 

 

Edited June 17, 2020 by Ghost1982

[JLogan3o13]

There are a couple ways to skin the proverbial cat, but here is a simple method that will work with any size collection:

$content = Get-Content <filepath.txt>

foreach ($line in $content) {
    Write-Host "Processing line $($content.IndexOf($line) + 1) out of $($content.Count)"
}

Notice the +1, as $content.IndexOf($line) will begin counting at 0. Post back if you have any questions.

[Ghost1982]

Meanwhile I did something like this:

$content = Get-Content input.txt
$lines = Get-content input.txt | Measure-Object -Line | Select-Object -ExpandProperty Lines
Foreach ($line in $content | Out-String -Stream | Select-String '.*' | Select-Object -Property LineNumber,Line)
{
    $number = $line | Select-Object -ExpandProperty LineNumber
    $ADgrp = $line | Select-Object -ExpandProperty Line
    Write-Host "Line" $number "of" $lines
    New-AdGroup -Name "$ADgrp" -SamAccountName $ADgrp
    Start-Sleep 2
}

 

 

Edited June 18, 2020 by Ghost1982