Passing a parameter by reference?

[ander868]

I was wondering if there was a way to pass a parameter to a function via reference?

For instance, in the code snippet below my variable is being passed in by value and my initial variable is not changed. Whats the easiest way to pass a pointer to the function so my initial variable is modified?

$outside_var = "null"

foo($outside_var)

Func foo($inside_var)
$inside_var = "Ive been changed!"
EndFunc

Im pretty sure it has to be possible, but I must just be missing the syntax. Also, how do I return something from a function?

$returned_var = foo()

Func foo()
$dummy_var = "Ive returned!"
[i]return $dummy_var ;??? no idea, just throwing something out there[/i]
EndFunc

Any help is appreciated.

Thanks

[Siao]

Help is in the helpfile.

Edited February 21, 2008 by Siao

[GEOSoft]

  ander868 said:

I was wondering if there was a way to pass a parameter to a function via reference?

For instance, in the code snippet below my variable is being passed in by value and my initial variable is not changed. Whats the easiest way to pass a pointer to the function so my initial variable is modified?

$outside_var = "null"

foo($outside_var)

Func foo($inside_var)
$inside_var = "Ive been changed!"
EndFunc

Im pretty sure it has to be possible, but I must just be missing the syntax. Also, how do I return something from a function?

$returned_var = foo()

Func foo()
$dummy_var = "Ive returned!"
[i]return $dummy_var;??? no idea, just throwing something out there[/i]
EndFunc

Any help is appreciated.

Thanks

Look up the keyword ByRef in the help file.

[ander868]

Geosoft,

Thanks. got exactly what I needed

Siao,

No one is forcing you read the forum if you have no desire to help. If you're just gonna post some useless comment then don't bother. Read the forum title.