Wierd Issue... @OSVersion resolves fine -- conditional not?

[thepip3r]

Func __checkOSVersion()
    Local $os = @OSVersion
    If $os <> "WIN_2003" or $os <> "WIN_2000" or $os <> "WIN_XP" Then
        MsgBox(0, "Operating System Incompatability (" & $os & ")", "Only Windows 2000, XP, and 2003 are supported right now.")
        Exit
    EndIf
EndFunc

@OSVersion reports as "WIN_XP" on my system but since I wrote this function and started using it, its' stopping me from accessing my program again. While I know I can comment it out until I figure out what's wrong, is there something glaringly obvious that's wrong with my logic as to why it IS in fact evaluating to true when it shouldn't be?? TIA.

[Jos]

Think about this line:

If $os <> "WIN_2003" or $os <> "WIN_2000" or $os <> "WIN_XP" Then

It need to be an AND relation:

Edited April 19, 2008 by Jos

[thepip3r]

i guess i can see how that would work (and it does in the code (ty Jos)) but why wouldn't "or" work??

My screwed up mind??

If $os is not equal to "WIN_2003"

or

$os is not equal to "WIN_2000"

or

$os is not equal to "WIN_XP"

True, True, False

nm... thnx again Jos.

[Jos]

It is simple when you see it: Whatever OS you have a minimum of 2 out of the 3 conditions is always TRUE thus the If is always true since you use an OR.

It helps when you read the statement out loud.