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Posted

Hi,

I have a excel file in d:\sla\test1.xls. how to open the file and read values from a certain column and row.

Thanks in advance,

Regards,

venkatraman

Posted

There is Excel UDF.

Search forum and look in AutoIt helpfile (from version 3.3 this UDF is included as standard UDF)

$sFilePath1 = @ScriptDir & "\test1.xls" ;This file should already exist

$oExcel = _ExcelBookOpen($sFilePath1)

i tried this. but the file is not opening.

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