Qousio Posted June 7, 2009 Share Posted June 7, 2009 (edited) Hello! I need to stringregexp a string that looks like this: value1: |01.23| Soo, I have used this StringRegExp($text, 'value1: \V\d\d\V\d\d', 1) And it works fine, the problem is, sometimes theres one number instead of two, so its |0.1|, in that case the above doesnt work. Using strinlen to find out how many numbers there are wouldnt work either, because it could be 00.1 or 0.11 etc. Edited June 7, 2009 by Qousio Link to comment Share on other sites More sharing options...
MrMitchell Posted June 7, 2009 Share Posted June 7, 2009 There are other ways, but you could just replace the second \d with {1,2}. StringRegExp($text, 'value1: \V\d{1,2}\V\d{1,2}', 1) Something like that Link to comment Share on other sites More sharing options...
Qousio Posted June 7, 2009 Author Share Posted June 7, 2009 There are other ways, but you could just replace the second \d with {1,2}.StringRegExp($text, 'value1: \V\d{1,2}\V\d{1,2}', 1)Something like thatThanks allot, works perfectly Link to comment Share on other sites More sharing options...
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