eSuppose that you discoverd from anaother universe that obeyed the following restrictions on

quantum numbers:

n>0

l+1<n

ml= +1 or -1

ms=+1/2

Assume that Hund's rule still applies, What would be the numbers of the first 3 noble gases in that universe

I've difficulty in figuring out the answers.

I guess the principal quantum number n is 2, because n has to be larger than the angular momentum number l plus one , even l is zero, the left side has same value as n.

And then I guess

n=2, l = 0

n=3, l = 0, 1

n=4, l = 0, 1, 2

n=5, l = 0, 1, 2, 3

and so on

Then I don't get the ml part.

Is it like that? [2, 0, +1, +1/2], [2, 0, -1, -1/2]

So the n=2 level has one orbital and 2 subshell, the total number of electron in level n=2 is to equal 2

Then n =3 [3, 0, +1, +1/2], [3, 0, -1, +1/2], [3, 1, +1, +1/2], [3, 1, -1, +1/2]

has 4 orbitals and 4 subshells and the total lof 4 electrons.

The first 2 noble gases atomic # is 2 and 6?

thx!