Range of numbers

[liten]

SImple question how do i set a value to have a range instead of 1 number such as $Value = 1 thru 10

instead of $value1 = 1

$value2 = 2

etc..

[billthecreator]

Local $Value[11]

For $r = 1 To 10
$Value[$r] = $r
Next

is this what you're looking for

[Exit]

For $i = 1 To 10
Assign ("Value"&$i,$i)
Next
MsgBox(0, '', Eval("value5"))

[liten]

not really more of something that can be used in this way

$numberrange = 1 to 50

if $currentnumber = $numberrange then

Func()

else

this says if $currentnumber is equal 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10 but wiht out havign to type that out

[Valuater]

Maybe....

$num_max = 50
$num_min = 1

If $currentnumber >= $num_min And $currentnumber <= $num_max Then

8)

[liten]

OMG your a Guinnessn

[BlackLumiere]

Hi all. It's been almost 11 years since this post. Even so, I would like to give a workaround function. This function is UDF and is inspired in the seq() function in R language. As it returns an 1D array, it also can be indexed easily. I hope can be useful to you all.

Cheers!

 

 

#include-once
#include <Array.au3>

Func seq($from, $to, $by = 1)
Local $vector[0]
Local $strVector

    for $e = $from to $to Step $by
        $strVector = $strVector & $e & ' '
    Next
    $strVector = StringTrimRight($strVector, 1)

_ArrayAdd($vector, $strVector, 0, ' ')
;~ _ArrayDisplay($vector)       <== [Debug]
ConsoleWrite('[1] ' &  $strVector & @CRLF)
Return $vector

EndFunc

 

;Test
$test1 = seq(1, 10)

$test2 = seq(1, 10, 3)

$indexTest3 = seq(1, 10, 1)
ConsoleWrite('[1] ' &  $indexTest3[0] & @CRLF)
ConsoleWrite('[1] ' &  $indexTest3[1] & @CRLF)

[JockoDundee]

On 8/14/2009 at 4:13 PM, liten said:

this says if $currentnumber is equal 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 10 but wiht out havign to type that out

you’re lucky $currentnumber is not a float