Question #243402

A 3Ω,6Ω,9Ω and 12Ω resistor are connected in series. What resistor that will consume the most

power?

power?

Expert's answer

First, we determine what's the equivalent resistance of the 3Ω and 6Ω resistors

Using the quick method, it's

(3×6)÷(3+6) or 2Ω

So the circuit's effectively 3Ω in series with 2Ω, 5Ω in total.

Current according to Ohm's Law is

I=V/R

V = 5V, R = 5Ω so I = 1A So, Ohm's Law again to calculate the voltage drop across the 3//2

combination,

V = IR, I is 1, R is 2, so the answer's 2V.

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