Sign in to follow this  
Followers 0
AfX78z90

How can i send DATA to a php site

5 posts in this topic

Hello

I would like to send data to my php site in a log.

Example: www.desgracado.com/info/log.php

I think the line of command is:

$g_IP = "www.desgracado.com/info/log.php"

$socket = DLLCall("wininet.dll","int","InternetOpen", "str", $g_IP, "int", 65432 )

;Code:

DLLCall( "wininet.dll", "int", "InternetOpenUrl", "int", $socket, "str", "Testando porra ")

Then my php page recieve the Msg "Testando porra"

Is that possible?

Share this post


Link to post
Share on other sites



#2 ·  Posted (edited)

Hello

I would like to send data to my php site in a log.

Example: www.desgracado.com/info/log.php

I think the line of command is:

$g_IP      = "www.desgracado.com/info/log.php"

$socket    = DLLCall("wininet.dll","int","InternetOpen", "str", $g_IP, "int", 65432 )

;Code:

DLLCall( "wininet.dll", "int", "InternetOpenUrl", "int", $socket, "str", "Testando porra ")

Then my php page recieve the Msg "Testando porra"

Is that possible?

<{POST_SNAPBACK}>

isn't data passed to the PHP script included in the URL after the .php?

Example http://www.some.site.com/page.php?variable1=data1&variable2=data2...variableN=dataN

Edited by Blue_Drache

Lofting the cyberwinds on teknoleather wings, I am...The Blue Drache

Share this post


Link to post
Share on other sites

isn't data passed to the PHP script included in the URL after the .php?

Example http://www.some.site.com/page.php?variable1=data1&variable2=data2...variableN=dataN

<{POST_SNAPBACK}>

Like this?

$g_IP = "www.desgracado.com/info/log.php?"

$socket = DLLCall("wininet.dll","int","InternetOpen", "str", $g_IP, "int", 65432 )

$data1 = "Test1"

$data2 = "Test2"

;Code:

DLLCall( "wininet.dll", "int", "InternetOpenUrl", "int", $socket, "str", $data1 & $data2)

Share this post


Link to post
Share on other sites

Like this?

$g_IP      = "www.desgracado.com/info/log.php?"

$socket    = DLLCall("wininet.dll","int","InternetOpen", "str", $g_IP, "int", 65432 )

$data1 = "Test1"

$data2 = "Test2"

;Code:

DLLCall( "wininet.dll", "int", "InternetOpenUrl", "int", $socket, "str", $data1 & $data2)

<{POST_SNAPBACK}>

Consider that the variable has to be declared in the .php script that you're trying to modify in the URL "command line" if you will.

for example, the variables modified in this line:

/forum/index.php?act=Post&CODE=02&f=2&t=10234&qpid=71454

are all inside the .php script. You'll have to pass the variable name as well as the data you want to modify.


Lofting the cyberwinds on teknoleather wings, I am...The Blue Drache

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!


Register a new account

Sign in

Already have an account? Sign in here.


Sign In Now
Sign in to follow this  
Followers 0