behav Posted October 14, 2009 Posted October 14, 2009 hi there, first sorry for my bad english im trying to check a string charakter but im doing something wrong my code $c5 = "001111111000011111110000110000000001100000000011111110001111111110011100011100000000011100000000111000110001110001100011101100000110011100011100111111110000011111000" $c6 = "000111110000011111110001110001110011000000000110111100001111111100011111111100110000111001100000110011000001100110000011001100001110011100011101111111110000011111000" $c8 = "000111111000011111110001110001111011100011110111000111001111001110001111111000111111111001110001110011000001110110000011101100000111011110011100011111111000011111000" $cK = "011110111100111101111000110011100001100110000011011100000111111000001111111000011111000000111110000001101110000011001100000110011100001100111000111111111001111111110" For $i = 0 To StringLen($str) $ss1 = StringMid($str, $i + 1, 1) $ss2 = StringMid($c5, $i + 1, 1) MsgBox(0,"The hex color is", $ss1 & "==" & $ss2) If $ss1 == $ss2 Then $mx = $mx + 1 EndIf Next only 3charakter are reading now and getting error
omikron48 Posted October 14, 2009 Posted October 14, 2009 (edited) For $i = 0 To StringLen($str) - 1 ;You forgot to adjust the max number of the loop $ss1 = StringMid($str, $i + 1, 1) $ss2 = StringMid($c5, $i + 1, 1) MsgBox(0,"The hex color is", $ss1 & "==" & $ss2) ;Just a guess but isn't it binary? If StringCompare($ss1, $ss2) == 0 Then ;You are comparing strings not numbers $mx = $mx + 1 EndIf Next Edited October 14, 2009 by omikron48
behav Posted October 15, 2009 Author Posted October 15, 2009 For $i = 0 To StringLen($str) - 1 ;You forgot to adjust the max number of the loop $ss1 = StringMid($str, $i + 1, 1) $ss2 = StringMid($c5, $i + 1, 1) MsgBox(0,"The hex color is", $ss1 & "==" & $ss2) ;Just a guess but isn't it binary? If StringCompare($ss1, $ss2) == 0 Then ;You are comparing strings not numbers $mx = $mx + 1 EndIf Next thank you, problem solved
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now