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how to give $all to Var1, Var2


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hello i want to give $all to varabuils like this.

$all = $var1&$var2&Var3

Did you mean

$all = $var1&$var2&$Var3


There is nothing wrong with that. SInce you say "give $all to varabuils" do you mean that you want all those variables to have the value that $all has? In which case you just need to have

$var1 = $all

$var2 = $all


If you have a lot of variables then use an array

For $n = 0 to UBound($var) - 1

$var[$n] = $all


Otherwise can you explain what the problem is? Ie what you want to do and what the problem is with what you have tried.

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I think it's not difficult to misinterpret what you're asking for. Anyway, I'll try to clarify something else, just in case this is what you actually need.

Read an AutoIt statement like:

$MyVariable = 1 + 2

this way:

AutoIt will evaluate the right-hand expression (whatever is on the right of the = sign) which is here 1 + 2 and it will come up with the value 3.

Then it will assign (store) this computed vale to the variable designated by the left-hand part. Thus it will store 3 into $MyVariable.

Instead of the sign = it would have been much clearer to write it:

$MyVariable ← 1 + 2

For practical reasons, this notation didn't get used in most languages (due to limited character set).

Read the = (assignment operator) as "becomes".

So if you want to assign $all to three variables, make it like Martin showed you: three assignments in sequence.

In AutoIt, & is the string concatenation operator, so your statement is almost valid (missing a $), albeit not obviously what you want.

BTW, read the help file with more care.

Edited by jchd

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