_GUICtrlRichEdit_SetBkColor() return wrong color?

[lsakizada 0]

I get wrong color in richedit control.

The following function supposed to paint the control with light blue but insteed the tint is reddish.

_GUICtrlRichEdit_SetBkColor($hReachEdit,0xEDF3FE)

you can check with the code that come with the examples of this function.

[Malkey 168]

The colour "0xEDF3FE" in in BGR format appears reddish.

The colour "0xEDF3FE" in in RGB format appears light blue.

; Enter colour in BGR format i.e. 0xBBGGRR, 
; where BB is blue channel hex value; GG - is green channel hex value; and, RR is red channel hex value
_GUICtrlRichEdit_SetBkColor($hRichEdit,"0xEDF3FE")

; This RegExpRepl converts BGR colour format to RGB colour format and visa versa. i.e. RGB format value looks like this 0xRRGGBB 
_GUICtrlRichEdit_SetBkColor($hRichEdit,StringRegExpReplace("0xEDF3FE","(.{2})(.{2})(.{2})(.{2})","\1\4\3\2"))

[lsakizada 0]

The colour "0xEDF3FE" in in BGR format appears reddish.

The colour "0xEDF3FE" in in RGB format appears light blue.

; Enter colour in BGR format i.e. 0xBBGGRR, 
; where BB is blue channel hex value; GG - is green channel hex value; and, RR is red channel hex value
_GUICtrlRichEdit_SetBkColor($hRichEdit,"0xEDF3FE")

; This RegExpRepl converts BGR colour format to RGB colour format and visa versa. i.e. RGB format value looks like this 0xRRGGBB 
_GUICtrlRichEdit_SetBkColor($hRichEdit,StringRegExpReplace("0xEDF3FE","(.{2})(.{2})(.{2})(.{2})","\1\4\3\2"))

Thank you Malkey! sovlve my issue.

Have a good one.