Getting part of an image

[d0n]

So i have an image, it is formatted in a grid format like so

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

what i want to do is, depending on where the red part is extract only a 3x3 square of that specific image

[] [] []

[] [] []

[] [] []

which function should i use to split the image into an X and Y coords (So the red in this example would be in X=3, Y=1)

Edited April 22, 2010 by d0n

[Malkey]

So i have an image, it is formatted in a grid format like so

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

what i want to do is, depending on where the red part is extract only a 3x3 square of that specific image

[] [] []

[] [] []

[] [] []

which function should i use to split the image into an X and Y coords (So the red in this example would be in X=3, Y=1)

I assume the coordinate system you are using is :-

X an Y coordinates are both zero based.

With reference to the top format pattern with 20 grids,

zero X is the left hand column, increasing to the right , and

zero Y is the bottom row increasing upwardly.

This makes the red square X=3, Y=1.

So, if a 3x3 square was extracted using the coordinate X=2, Y=1, from your 20 grid example, then I assume the pixel at coordinate X=3, Y=1.would appear left of center of the 3x3 square.

or

Does the image you have, have the height divided into 4 row and the width divided into 5 column. And, when you select one of the 6 internal grid areas, the 3x3 square you extract contains 9 /20 th of the image?

What format is the extracted 3x3 square?

Is it an image to be saved as a jpg file? or,

9 pixels?, or,

something else?

The answer to these questions may help someone else figure out which function you should use.

[d0n]

the image is more than 9 pixels, i think each square is about 9 pixel itself

then there is a black boarder around it, then some spacing between each square.

The X and Y are zero based so from my example of 20 squares the red is located at X = 3 and Y = 1

zero X is the left hand column, increasing to the right , and

zero Y is the bottom row increasing upwardly.

the image is in JPG format