[Solved]Need Stringregexp() Help

[Fire]

Hi to All Great Autoit Community.

Guys i need stringregexp() help again.

I`m trying to parse apache logs in win environment for this line:

/aproxy/ HTTP/1.1

In fact apache logs format is like this:

http://httpd.apache.org/docs/1.3/logs.html

Snippet from apache log:

IP adrress of user - - [22/May/2010:07:17:35 -0700] "GET /aproxy/index.php?q=ROT13ENCODEDURLHEREGOES" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1)"

From ssh in Linux this is not problematic extract it:

Like this:

user@myhost.com /logs
$ grep -r '/aproxy/' accesslog_somemysite_2010 >444.txt &

Also this way works in CYGWIN too.

I`m trying using AUTOIT parse this log file for this pattern

/aproxy/ HTTP/1.1

Here is sample:(Using StringRegExp From Help file)

It didn`t parse log file and exit.

But i think theris problem with \ (slash).

Please Guys help me in this too.

Thanks in advance.

$nOffset = 1


$str=FileRead(@ScriptDir&"\file.txt")


While 1
$array = StringRegExp($str, '(?i)/aproxy/ (.*?)(?i)HTTP/1.1', 1, $nOffset)


    If @error = 0 Then
    $nOffset = @extended
    Else
    ExitLoop
    EndIf
    for $i = 0 to UBound($array) - 1
    msgbox(0, "RegExp Test with Option 1 - " & $i, $array[$i])
    Next
WEnd

Edited May 25, 2010 by Fire

[Fire]

Sorry.I figure it out.Nevermind! Seems problem with spaces.

Now It works.

Hope it would be usefull.

/Solved

$nOffset = 1


$str=FileRead(@ScriptDir&"\file.txt")


While 1

 $array = StringRegExp($str, '(?i)/aproxy/(.*?)(?i)HTTP/1.1', 1, $nOffset)




    If @error = 0 Then
    $nOffset = @extended
    Else
    ExitLoop
    EndIf
    for $i = 0 to UBound($array) - 1
    msgbox(0, "RegExp Test with Option 1 - " & $i, $array[$i])
    Next
WEnd

Edited May 25, 2010 by Fire