Test type of a variable

[akorx 0]

Hi guys,

Sorry for my bad english i'm french...

Do you know how can i test the type of a variable ? i use "cmdline" command to give parameters to my script and parameters must be integers :

exemple :

myscript 1 2 3

if i make a mistake like this :

myscript 1 a 3

it works ! the string "a" seems to be recognized as the number "0" and i don't want !! have you got an idea to solve my problem ?

[whim 1]

Hi akorx !

AutoIt has a function IsInt()

[jchd 989]

Use the Is* functions: IsNumber, IsInt, IsFloat, ...

This is correct, Number("a") = 0 by convention/feature.

Et voilà.

[akorx 0]

Hi akorx !

AutoIt has a function IsInt()

Thanks you for your help but it does't work ! in my exemple the string "a" is recognize as a "0" (zero) and so the function "isint()" returns "1" (= true"), however "a" is a string and not a number...

Edited December 1, 2010 by akorx

[jchd 989]

Pardon ?

What does

ConsoleWrite(IsInt("a") & @LF)

print for you?

[akorx 0]

Pardon ?

What does

ConsoleWrite(IsInt("a") & @LF)

print for you?

It returns "0" ...

[jchd 989]

Well, and

ConsoleWrite(IsInt("3") & @LF)

[akorx 0]

Well, and

ConsoleWrite(IsInt("3") & @LF)

Same thing, it returns "0"...

Someone should have known the problem... no ?

I'm going to eat, i'll be back in few minutes...

Edited December 1, 2010 by akorx

[hannes08 35]

Hi akorx,

please try StringIsInt(). This gives you the right answers...

ConsoleWrite($CmdLine[1] & @TAB & StringIsInt($CmdLine[1]) & @CRLF)
ConsoleWrite($CmdLine[2] & @TAB & StringIsInt($CmdLine[2]) & @CRLF)

or

ConsoleWrite("10" & @TAB & StringIsInt("10") & @CRLF)
ConsoleWrite("abc" & @TAB & StringIsInt("abc") & @CRLF)

Regards,

Hannes

[Alek 1]

StringIsInt should do the job

edit:

argh, too slow

Edited December 1, 2010 by Alek

[jchd 989]

Geez, I'm really slow today.

Of course StringIsInt is the right function.

[akorx 0]

Yes it works !!!

Big thanks guys for your help, you are kings !!!!!!