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Thlitmi

[SOLVED] Syntax way: $a[$n]=StringLen($a2[$a3[$n]])

9 posts in this topic

#1 ·  Posted (edited)

$array[$number]=StringLen($array2[$array3[$number]])

Is not a valid syntax.

But I do not know how else I would solve this problem.....

I do not know under what name of "something" I should search help abou this problem...

Index of array2 is defined by values of array3 , how to do it ?

//edit:

And of-course, I work with this in loop, where $number is not static)

Edited by Thlitmi

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Your problem is very likely semantics since that's perfectly valid syntax.


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eMyvnE

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That should mean,that I have error somewhere else .. !

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That should mean,that I have error somewhere else .. !

Post source for more help then.

I'm a compulsive poster. When I post something, come to read it at least 5 minutes later after the posting, because I will edit it. I edited even this signature a few minutes later after I wrote it.

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$number[x] is sometimes equal to number -1

Thats not good, because there is no array index number -1

I will try to filter it to see if it'll help.

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After applying the fiter, it worked :graduated:

So the error is, that one of my functions returned value that can not be used for array. It was like invisible error....

[sOLVED]

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[sOLVED]

wow ! :-D

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