..

[Deathbringer]

Edited January 8, 2011 by JosIsaFucktard

[Jos]

In this case it's easy: 0x15 or 21 because BitAND has no purpose

$i = BitAND(21, 0xFF)

Edited December 27, 2010 by Jos

[Jos]

Oops, I guess I should have Googled more before posting. A bitwise AND operation cannot be reversed.

correct.. you can only figure out all possible options (except for the one you gave as example.