$var = $var + 1 problem

[ViciouS]

noob question for sure.

$var = 0

$var = $var + 1

why is it that its creating 1111111111, instead of 1 2 3 4 5 6 7..... like i want it to?

[Rogue5099]

$var = 0
For $x = 1 To 10
    $var = $var + 1
    MsgBox(0, "", $var)
Next

This works for me???

Edited April 10, 2011 by rogue5099

[MvGulik]

This:

$var = 0
$var = $var + 1
$var = $var + 1 ;; etc

Will NOT produce "11...etc". (not even if you used quoted value's) ... your probably using '&' instead of '+' in your real code.

Tip:

Show your real code instead of your interpretation of what you think your/the code is doing.

(apply's to all, just double, or even triple, for beginners ... or noob's if you like.)

Edited April 10, 2011 by iEvKI3gv9Wrkd41u

[smartee]

The addition operation is not treated as string concatenation in the AutoIt language. Try these examples

$var = 1
$var = $var + 1
MsgBox(64, "Test 1", $var)

$var = "String"
$var = $var + 1
MsgBox(64, "Test 2", $var)

$var = "String"
$var = $var + "1"
MsgBox(64, "Test 3", $var)

If the addition operation is used with strings, then the statement is evaluated using the numerical representation of the expression contained in the string. To see/understand the numeric representation of several string expressions see the Number() function in the help file.