Help with Strings

[HockeyFan]

I need to pull the file name out of a files full path, for example:

I would like to pull "Firefox Setup 4.0.exe" from the this path: C:\Software\Firefox v4\Firefox Setup 4.0.exe

I've played around with this, but I'm not getting the results that I expected.

$Path = "C:\Software\Firefox v4\Firefox Setup 4.0.exe"
$String = StringRight($Path, StringInStr($Path, "\", 0, -1)) 
MsgBox(0,"File name: ", $String)

What's the best way to perform this even if the path was "C:\Firefox Setup 4.0.exe"?

Thanks!

[somdcomputerguy]

Try with this UDF, _PathSplit. Good luck!

[HockeyFan]

Try with this UDF, _PathSplit. Good luck!

Thank you!!!

That UDF works perfectly. Thanks for the pointer!!

$Path = "C:\Software\Firefox v4\Firefox Setup 4.0.exe"
$PathArray = _PathSplit($Path, $szDrive, $szDir, $szFName, $szExt) 
MsgBox(0,"File name: ", $PathArray[3] & $PathArray[4])

[somdcomputerguy]

You bet. Good luck with your project.

[GMK]

An alternate solution:

$sPath = "C:\Software\Firefox v4\Firefox Setup 4.0.exe"
$aSplit = StringSplit($sPath, "\")
$sFileName = $aSplit[1] & "\" & $aSplit[$aSplit[0]]

Edit: Missed the front of the path.

Edited June 9, 2011 by GMK