StringRegExp pattern

[ASut]

Hi, How can I modify the pattern to make it the output as below

1
ABC
123ABC

instead of

1
12<test>ABC
123ABC

Which means ignore the broken tag.

Thanks in advance.

$array = StringRegExp('<test>1</test> <test>12<test>ABC</test> <test>123ABC</Test>', '<(?i)test>(.*?)</(?i)test>',3)
for $i = 0 to UBound($array) - 1
    msgbox(0, "Test - " & $i, $array[$i])
Next

[Jos]

You are sure that this bit is really the input: "<test>12<test>ABC" and is not "<test>12</test>ABC"?

if so try: '<(?i)test>(.*?)<[/](?i)test>'

Jos

Edited June 26, 2011 by Jos

[ASut]

You are sure that this bit is really the input: "<test>12<test>ABC" and is not "<test>12</test>ABC"?

if so try: '<(?i)test>(.*?)<[/](?i)test>'

Jos

I'm very sure it is "<test>12<test>ABC</test>".

But the pattern is not work for me.

Btw, thanks for the help.

[SmOke_N]

"(?i)<test>(.+?)(?=<)"

Edited June 26, 2011 by SmOke_N
Needed a "Look Ahead" pattern

[Malkey]

Hi, How can I modify the pattern to make it the output as below

1
ABC
123ABC

...

Try this.

#Include <Array.au3>

; Positive assertions of both look behind and look ahead.
;$array = StringRegExp('<test>1</test> <test>12<test>ABC</test> <test>123ABC</Test>', "(?i)(?<=<test>)([^<]+)(?=</test>)" ,3)
;or
;$array = StringRegExp('<test>1</test> <test>12<test>ABC</test> <test>123ABC</Test>', "(?i)(?:<test>)([^<]+)(?:</test>)" ,3)
;or
$array = StringRegExp('<test>1</test> <test>12<test>ABC</test> <test>123ABC</Test>', "(?i)(?:>)([^<]+)(?:</)" ,3)

_ArrayDisplay($array)

#cs
All patterns return an array of:-
1
ABC
123ABC
#ce

[ASut]

Thanks, them work fine for me.

RegExp is very difficult to learn.