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dirty

path is not valid anywhere anymore after use of fileopendialog

8 posts in this topic

So i have a script reading path from INI file.

ImagePath=.\Project Pictures\Core PeelPacks\7.5 Laser bridge.JPG

When i start the script, picture is drawn in GUI and is executable by shellexzecute

The input field for the image path also shows .\Project Pictures\Core PeelPacks\7.5 Laser bridge.JPG

and this is exactly what shellexecute executes. It does it by guictrlread ($inputfieldofanimage)

But when i start any function on the same scriutp that has anything to do with fileopendialog,

.\Project Pictures\Core PeelPacks\7.5 Laser bridge.JPG is no longer valid.

And without changing input field in gui, shellexecute can no longer find this file :graduated:

I dont understand why.

Is something changes in the script behavior when fileopendialog() is used ?

Thanks in advance

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dirty,

If you read the Help file page for FileOpenDialog, you will see that:

"@WorkingDir is changed on successful return"

So try changing it back to the original using FileChangeDir once you have used the dialog. :graduated:

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i need to use relative path only. this is one limitation i want to implement so that users wont have to worru about having to fix path in each generated ini file.

Just trying to keep the script as simple as i can with less then 2000 lines ;) (thats too much for me)

Wow i didnt know that FileChangeDir existed.

So how do i use this to reset the default path to relative using FileChangeDir ?

Not sure what parameters to give to it :graduated:

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i was also trying to isolate the relative directory subfolders.

$AdminDefaultPicturesPath = ".\Default Pictures Folder"

$EditMainImage = FileOpenDialog("Open Picture file", $AdminDefaultPicturesPath, "Picture files (*.JPG;*.JPEG;*.BMP) | All (*.*)")

Dim $zDrive,$zPath,$zFile,$zExt

_PathSplit ($EditMainImage,$zDrive,$zPath,$zFile,$zExt)

When i do GUICtrlSetData($MainImagePath, $AdminDefaultPicturesPath & $zPath & $zFile & $zExt)

i get in trouble because $zPath gives not just the selected folder from relative location, but provides whole path without Drive and filename.

For example

Current working directory is

F:\Autoit projects\CS Surgical Inventory management\Source\Project Pictures

$EditMainImage returns F:\Autoit projects\CS Surgical Inventory management\Source\Project Pictures\Subfolder\File.jpg

Splitting path using $AdminDefaultPicturesPath & $zPath, i get

.\Default Pictures Folder\Autoit projects\CS Surgical Inventory management\Source\Project Pictures\Subfolder\File.jpg

but i need

.\Default Pictures Folder\Subfolder\File.jpg

how do i achieve this goal ?

Thanks for replies and thanks in advance

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_WinAPI_GetOpenFileName() with the OFN_NOCHANGEDIR parameter, and _PathGetRelative()


I see fascists...

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Post the result of @WorkingDir before you call FileOpenDialog() and the result of @WorkingDir after you call FileOpenDialog.

It looks to me like this is easily managed without splitting the path at all and I think I have simple code to do it but I want to check to be sure.


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#8 ·  Posted (edited)

_WinAPI_GetOpenFileName() with the OFN_NOCHANGEDIR parameter, and _PathGetRelative()

Can you give me an example ?

Am not sure how to use your references.

Keep in mind that i should be able to go deeper into suborders bu not above working folder.

Edited by dirty

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