Is there a Short for Reading and Writing a Char in a String?

[Zohar]

Hi

If I have a String, and I need to Read and Write Specific Chars in it,

(not to insert or delete any chars, but only to Read and or Edit the Existings chars)

Is there any Short for it?

Right now what I use, is StringMid($String,$i,1), to get the Char in Position i.

To Set a char in postion i, it's even longer in terms of writing..

In most proghramming language, a string can also be treated as an array of chars,

Can it be used similarly in AutoIt too?

Thank you

Zohar

[johnmcloud]

Maybe StringToASCIIArray?

[czardas]

Perhaps StringRegExpReplace, but I'm not sure if you want global replacements or something different. You haven't mentioned much about the type of editing you want.

[Zohar]

Perhaps StringRegExpReplace, but I'm not sure if you want global replacements or something different. You haven't mentioned much about the type of editing you want.

The editting is not according to a spcfici known content,

but according to Char position.

The only known thing is Char position,

that's why I ask If I can treat a String as a Char Array - that way I can edit any char independently.

Maybe StringToASCIIArray?

Thank you,

looks like a nice idea..

Also to be used with StringFromASCIIArray() later, to make it a string back again..

Thanks!

Edited February 19, 2013 by Zohar

[johnmcloud]

Thank you,

but if the string is Unicode? It won't work well?

You can use in alternative StringSplit, if you use "" (an empty string) as the splitter it will split on every character, so does't matter.

[Malkey]

Here is an example of using character positions in StringRegExpReplace.

Local $sString = "Right now what I use, is StringMid($String,$i,1), to get the Char in Position i." & @CRLF & _
        "To Set a char in postion i, it's even longer in terms of writing.."

; 7th, 8th, 9th characters in string is "now" to be replaced with "then".
ConsoleWrite( _StringMidReplace($sString, 7, 3, "then") & @LF)

Func _StringMidReplace($String, $iStart, $iCount, $sReplacement)
    Return StringRegExpReplace($sString, "(?s)(.{" & ($iStart - 1) & "})(.{" & $iCount & "})(.*)", "\1" & $sReplacement & "\3")
EndFunc   ;==>_StringMidReplace

[Zohar]

You can use in alternative StringSplit, if you use "" (an empty string) as the splitter it will split on every character, so does't matter.

Cool.

Thank you

Here is an example of using character positions in StringRegExpReplace.

Return StringRegExpReplace($sString, "(?s)(.{" & ($iStart - 1) & "})(.{" & $iCount & "})(.*)", "\1" & $sReplacement & "\3")

Thank you Malkey, but Regular Expressions make it longer here, not shorter like I wished