Help with $arr[ ] - $arr[ ]

[Runner]

I can't figure for the life of me why I keep getting a zero result for line 10 in the following code?

Local $arr[15]
Local Const $sFilePath = "C:\IRTest2.txt"
Local $hFileOpen = FileOpen($sFilePath, 0) ; handle for file
  
$sFileRead = FileRead($hFileOpen)
FileClose($hFileOpen)

Local $arr = StringSplit($sFileRead, "," & @LF)

   ConsoleWrite($arr[3] - $arr[1])

IRTest2.txt file is this:

"01348","0","01355","0","01473","1","01498","0","01533","1","01558","0","01593","1"

 If I change the ' - ' to '&' in line 10 I get this output:>  "01355""01348". So the variables have the right values.

But this works:

Local $arr[20]
$arr[11] = "01348"
$arr[13] = "01355"
ConsoleWrite($arr[13] - $arr[11])

Output for this one is 7.

 

So what am I missing? I've tried using Number($arr[3]... ,etc still returns zero.

[DW1]

Remove the quotes from the file when you read it (or elsewhere in the script) so that the variable isn't forced to be treated as a string.

For example, replace your FileRead with:

$sFileRead = StringReplace(FileRead($hFileOpen), '"', '')

EDIT: If it is still not clear why your second test example worked but the first script reading the file failed, consider that keeping the quotes when you read the file would actually make the second example look like the following snippet and also fail (when you treat the strings as numbers in the example, they are equal to zero):

Local $arr[20]

$arr[11] = '"01348"'

$arr[13] = '"01355"'

ConsoleWrite($arr[13] - $arr[11])

Edited January 22, 2014 by DW1

[BrewManNH]

Your numbers have quotes around them in the array. They're seen as strings because of them, and string minus string equals 0.

[Runner]

But it works in the last example? Why?

[DW1]

But it works in the last example? Why?

As I added to my post, because you are not keeping quotes in the second script, forcing the variable to be read as a string.  See my edited post above.

[Runner]

Excellent! I've got it now.

Thanks for the added edit that made it clear.