Need help with converting a simple batch file

[BDizzel1982]

Hey everyone I'm new to autoit and was look for a little assistance. I'm trying to convert a simple batch file that runs the following command into an autoit script but keep getting syntax errors, any help converting this would be greatly appreciated.

 

@ECHO OFF

 

 

echo ====================================

echo Removing Boot Guard

echo ====================================

 

 

C:Program Files (x86)PGP CorporationPGP Desktoppgpwde.exe" --remove-bypass --admin-passphrase "Passw0rd!"

 

 

 

[JLogan3o13]

Look at Run or ShellExecute in the help file. Try it out, and post what you have if you continue to see issues.

[BDizzel1982]

Hey JLogan3o13 I tried the Run command and this is what I get

Run('C:\Windows\System32\cmd.exe')

Send("c:program files (x86)pgp corporationpgp desktoppgwde.exe --remove-bypass --admin-passphrase "Passw0rd!")

 

>"C:\Program Files (x86)\AutoIt3\SciTE\AutoIt3Wrapper\AutoIt3Wrapper.exe" /prod /in "V:test 2.au3"

+>10:55:23 Starting AutoIt3Wrapper v.2.1.4.4 SciTE v.3.3.7.0 ;  Keyboard:00000409  OS:WIN_7/Service Pack 1  CPU:X64 OS:X64    Environment(Language:0409  Keyboard:00000409  OS:WIN_7/Service Pack 1  CPU:X64 OS:X64)

>Running AU3Check (3.3.10.2)  from:C:Program Files (x86)AutoIt3

"V:test 2.au3"(2,104) : error: syntax error

Send("c:program files (x86)pgp corporationpgp desktoppgwde.exe --remove-bypass --admin-passphrase "Passw0rd

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^

V:test 2.au3 - 1 error(s), 0 warning(s)

!>10:55:23 AU3Check ended. Press F4 to jump to next error.rc:2

+>10:55:23 AutoIt3Wrapper Finished..

>Exit code: 2    Time: 0.871

 

 

I'm not sure how to format the "Passw0rd!" which I need the command to enter

[JLogan3o13]

How about something like this?

ShellExecute(@ProgramFilesDir & '\PGP Corporation\PGP Desktop\pgpwde.exe', '--remove-bypass --admin-passphrase "Passw0rd!"')

[BDizzel1982]

Thank you that worked perfectly