# Hex() treats some numbers differently?

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I was trying to write a routine that moved through a decimal range and gave me the difference in hex.

The difference would be correct in decimal, but when I tried to convert it to hex it always returned zero.

After struggling with this for a while thinking I was doing something wrong I finally broke out the code I was struggling with and built this small test.  It does not behave like I expect.

Is this a bug or is it working-as-designed and I just don't understand some nuance of "string" numeric vs. "real" numeric?

Teddy

` `
\$range = "2010-2023"
\$rl = StringLeft(\$range, 4)
\$rr = StringRight(\$range, 4)
ConsoleWrite("Diff (without hex())      =" & (\$rr - \$rl) & @CRLF)                       ;Diff (without hex())      =13
ConsoleWrite("Hex without Number()      =" & Hex(\$rr - \$rl, 2) & @CRLF)                 ;Hex without Number()      =00
ConsoleWrite("Hex with Number() on sum  =" & Hex(Number(\$rr - \$rl), 2) & @CRLF)         ;Hex with Number() on sum  =00 <-- this one is really confusing
ConsoleWrite("Hex with Number() on each =" & Hex(Number(\$rr) - Number(\$rl), 2) & @CRLF) ;Hex with Number() on each =0D

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```\$range = "2010-2023"
\$rl = StringLeft(\$range, 4)
\$rr = StringRight(\$range, 4)
ConsoleWrite(VarGetType(\$rr - \$rl) & @CRLF)```

Because \$rr - \$rl isn't what you think it is.

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Thanks ... the VarGetType really helped make more sense out of this behavior.

I've changed that original to \$rl = Int(StringLeft(\$range,4)) and all is well.

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