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Eiyu

rename the first letters of a file

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Eiyu

Hello,
I will need to rename the first letters of all the files contained in a folder.
example:
My folder contains the following files:

"D:\Manual_20150620013430.txt"
"D:\Manual_20150620014428.txt"
"D:\Manual_20150620014604.txt"
... After "_" numbers are never identical

I want it to be like this after running the script:
"D:\Alarm_20150620013430.txt"
"D:\Alarm_20150620014428.txt"
"D:\Alarm_20150620014604.txt"

I found several methods, copy and paste with another name, move with another name and other ...
I'm bad, or not smart enough XD
Thank you in advance

 

Edited by Eiyu

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jvds

maybe rename with the DOS 'ren a.txt b.txt'
or with

run(@ComSpec&' /C '&@ScriptDir&'/ren a.txt b.txt')

 

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BrewManNH

If all the file names start with Manual_ you can use the DOS ren command to do it very easily.

Run(@ComSpec & " /c ren D:\Manual_*.txt Alarm_*.txt", "", @SW_HIDE)

This command will rename any file that starts with the word Manual followed by an underscore, and change the word Manual to Alarm. It will not show a window when doing it.


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Eiyu

Thank you it's almost this:
This is what it does:

D:\Manual_20150620110854.txt

-> D:\Alarm__20150620110854.txt

There are two "_"  :-S

Thank you

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Rockerfeller

You could try this then. Run(@ComSpec & " /c ren D:\Manual*.txt Alarm*.txt", "", @SW_HIDE) I also seen a filerename function in example scripts or wiki.

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