Subtract days with Date Format

[DigDeep]

I have 2 sections here.

1st portion is the correct format I need in mm/dd/yyyy.

But I would like to simplify the 2nd portion instead of writing multiple lines.along with getting the date format in MM/DD/YYYY.

Local $File = FileGetTime(FilePatch)
Local $sNewDate1 = $File[1] & "/" & $File[2] & "/" & $File[0] ; Changing the format as mm/dd/yyyy

Local $sJulDate = _DateToDayValue(@YEAR, @MON, @MDAY)
Local $Y, $M, $D
$sJulDate = _DayValueToDate($sJulDate, $Y, $M, $D)
$GetDate = $M & "/" & $D & "/" & $Y
;~ MsgBox(0, "", $GetDate) ; Today


; ===>>> Can we siplify this to get the Date format in MM/DD/YYYY
    Local $Yesterday1 = _DateAdd('d', -1, _NowCalcDate()) ; Yesterday
    Local $Yesterday2 = _DateAdd('d', -2, _NowCalcDate()) ; 2 days ago
    Local $Yesterday3 = _DateAdd('d', -3, _NowCalcDate()); 3 days ago   

    $aYesterday = StringSplit($Yesterday1, "/")
    $sYesterdayFormatted1 = $Yesterday1[2] & "/" & $Yesterday1[3] & "/" & $Yesterday1[1]
    
    $aYesterday = StringSplit($Yesterday2, "/")
    $sYesterdayFormatted2 = $Yesterday2[2] & "/" & $Yesterday2[3] & "/" & $Yesterday2[1]    
    
    $aYesterday = StringSplit($Yesterday3, "/")
    $sYesterdayFormatted3 = $Yesterday3[2] & "/" & $Yesterday3[3] & "/" & $Yesterday3[1]    
; ===>>> Can we siplify this to get the Date format in MM/DD/YYYY   
    
    
If $sNewDate1 = $GetDate Or $sNewDate1 = $sYesterdayFormatted1 Or $sNewDate1 = $sYesterdayFormatted2 Or $sNewDate1 = $sYesterdayFormatted3 Then ; FileDate is either today or less than 3 days then it's fine. 
    MsgBox(0, '', 'Pass')

Else
    MsgBox(0, '', 'Fail')
EndIf

 

[mikell]

12 hours ago, DigDeep said:

; FileDate is either today or less than 3 days then it's fine.

Why don't you compare using _DateDiff  ?

Local $File = FileGetTime(FilePatch)
Local $sFileDate = $File[0] & "/" & $File[1] & "/" & $File[2]
If _DateDiff("D", $sFileDate, _NowCalcDate()) > 3 Then MsgBox(0, '', 'Fail')

 

[Danp2]

Local $sJulDate = _DateToDayValue(@YEAR, @MON, @MDAY)
Local $Y, $M, $D
$sJulDate = _DayValueToDate($sJulDate, $Y, $M, $D)
$GetDate = $M & "/" & $D & "/" & $Y

Mikell has given you the solution, but I just had to ask about this code. Couldn't this have just been written with a single line?

$GetDate = @MON & "/" & @MDAY & "/" & @YEAR

 

[DigDeep]

Thanks @mikell... I was trying out the same but wasn't able to align the format correctly. I can use your's as per needed.

Thanks @Danp2 too for giving your time. I tried your suggestion prior mikell replied. But that was going a little long to have less than 7 days. But I think I can utilize your's way too with something else I have in future.